Exercise Program Homework: Calculating Jumps & Time Needed

  • Thread starter Thread starter Emethyst
  • Start date Start date
  • Tags Tags
    Exercise Program
AI Thread Summary
A 75kg individual aims to burn 500 food calories through high jumps in an exercise program, with human muscle efficiency at 20%. The potential energy for each jump is calculated, and the energy burned is derived from this value. Initial calculations led to confusion over calorie conversion, with the correct understanding that 1 food calorie equals 1000 calories. After correcting the conversion, the resulting energy calculations still yield an incorrect total, suggesting further errors in the process. Clarification on the energy calculations and conversions is needed to accurately determine the number of jumps and session time required.
Emethyst
Messages
117
Reaction score
0

Homework Statement


A 75kg person is put on an exercise program by a physical therapist, the goal being to burn up to 500 food calories in each daily session. Human muscles are about 20% efficient in converting energy into mechanical energy. The exercise program consists of a set of consecutive high jumps, each one 50cm into the air and lasting 2s. How many jumps should the person do per session, and how much time should be set aside for each session?


Homework Equations


Kinetic energy, potential energy, conservation of energy


The Attempt at a Solution


I tried to solve this by first finding the potential energy of the person, and then using this value to calculate the energy burned by multiplying it by 0.20. Afterwards, I divided 2092J (obtained by converting the 500 food calories into joules) by the energy burned. The value I obtained was much too small, so I know I'm going wrong somewhere, I just don't know where, although I think I might have converted the food calories wrong. If anyone can point me in the right direction here it would be greatly appreciated, thanks in advance.
 
Physics news on Phys.org
Remember a food calorie is really 1000 calories (ie 1kcal)
so 1 joule = 2.3901×10^−4 kcal or 1 kcal is about 4184 joules
 
Ahh I thought I converted it wrong, thanks for pointing out my mistake, however, if I use the new value that gives me, I get an answer too large (2.85x10^4 when it should be 1.1x10^3); is there some other place I'm going wrong here?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top