Recent content by epuen23
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Where Is the Center of Mass of a Leg?
Oh my gosh, thank you so much guys! X 2.7 * 9.6 = 25.92 2.1 * 2.9 = 6.09 1.5 * 0.9 = 1.35 SUM OF TORQUES = 33.39 DIVIDED BY SUM OF MASS = 13.4 33.39 / 13.4 = 2.5 Y 3.2 * 9.6 = 30.72 2.5 * 2.9 = 7.25 1.9 * 0.9 = 1.71 SUM OF TORQUES = 39.68 DIVIDED BY SUM OF MASS = 13.4 39.68 / 13.4 = 3- epuen23
- Post #9
- Forum: Introductory Physics Homework Help
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Where Is the Center of Mass of a Leg?
So I know T (Torque) = F (Force) * ⊥d (Perpendicular Distance). Would it be: 2.7 * 9.6? Am I even close?- epuen23
- Post #7
- Forum: Introductory Physics Homework Help
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Where Is the Center of Mass of a Leg?
I was having a hard time uploading screenshots of the equations/problem. I think I got it to work now.- epuen23
- Post #4
- Forum: Introductory Physics Homework Help
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Where Is the Center of Mass of a Leg?
I hope this helps.- epuen23
- Post #3
- Forum: Introductory Physics Homework Help
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Where Is the Center of Mass of a Leg?
The center of mass of someone's thigh, shank, and foot are located at the following coordinates: Thigh: (2.7, 3.2) Shank: (2.1, 2.5) Foot: (1.5, 1.9) If the masses of them are respectively 9.6, 2.9, and 0.9 kg, where is the location of the entire leg? ANSWER: CM = (2.5, 3)I'm having trouble...- epuen23
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- Center Center of mass Mass
- Replies: 8
- Forum: Introductory Physics Homework Help
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Calculating the Displacement (Having Constant Acceleration)
Orodruin, thank you so much. I guess it was just a silly mistake I made and didn't catch it. Thank you!- epuen23
- Post #5
- Forum: Introductory Physics Homework Help
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Calculating the Displacement (Having Constant Acceleration)
Oh. My. Gosh! Thank you so much. I don't know how I missed that. Thank you!- epuen23
- Post #4
- Forum: Introductory Physics Homework Help
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Calculating the Displacement (Having Constant Acceleration)
I'm just having trouble understanding 1) how to plug in the formulas correctly and 2) the correct manner of attacking this. I feel like I'm missing something basic/simple. Any help is greatly appreciated! So far I've got: D = (0) + .5(2.2m/s^2 x 2.4s)^2 Enrique- epuen23
- Thread
- Acceleration Constant Constant acceleration Displacement
- Replies: 4
- Forum: Introductory Physics Homework Help