Where Is the Center of Mass of a Leg?

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SUMMARY

The center of mass (CM) of a human leg, comprising the thigh, shank, and foot, is calculated using their respective coordinates and masses. The thigh is located at (2.7, 3.2) with a mass of 9.6 kg, the shank at (2.1, 2.5) with a mass of 2.9 kg, and the foot at (1.5, 1.9) with a mass of 0.9 kg. The overall center of mass of the leg is determined to be at the coordinates (2.5, 3) after calculating the torques and dividing by the total mass of 13.4 kg.

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epuen23
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Homework Statement
The center of mass of someone's thigh, shank, and foot are located at the following coordinates:

Thigh: (2.7, 3.2)

Shank: (2.1, 2.5)

Foot: (1.5, 1.9)

If the masses of them are respectively 9.6, 2.9, and 0.9 kg, where is the location of the entire leg?


ANSWER:

CM = (2.5, 3)
Relevant Equations
CMx = Xprox + L%*(Xdist - Xprox)
CMy = Yprox + L%*(Ydist - Yprox)
CMbody = E*(CMseg*Mseg)/Mtotal
The center of mass of someone's thigh, shank, and foot are located at the following coordinates:
Thigh: (2.7, 3.2)
Shank: (2.1, 2.5)
Foot: (1.5, 1.9)
If the masses of them are respectively 9.6, 2.9, and 0.9 kg, where is the location of the entire leg?

ANSWER:
CM = (2.5, 3)I'm having trouble figuring out the steps for this. I feel like I need to know the Length % in order to complete the formula but am lost as to how to get this. Thank you for any help you may be.

-E
 
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Please define the parameters in your equations.
 
I hope this helps.
 

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Chestermiller said:
Please define the parameters in your equations.
I was having a hard time uploading screenshots of the equations/problem. I think I got it to work now.
 
So in the bottom of the screenshot, it talks about calculating the torques for each segment. Do you know how to do that?
 
Think about a simpler problem, like a 1 dimensional bar with weights attached at different points. How would you find the center of mass? Now how would this be expanded to 2 dimensions?
 
scottdave said:
Think about a simpler problem, like a 1 dimensional bar with weights attached at different points. How would you find the center of mass? Now how would this be expanded to 2 dimensions?

So I know T (Torque) = F (Force) * ⊥d (Perpendicular Distance).
Would it be: 2.7 * 9.6? Am I even close?
 
epuen23 said:
So I know T (Torque) = F (Force) * ⊥d (Perpendicular Distance).
Would it be: 2.7 * 9.6? Am I even close?
Yes, you're on the right track.
 
Chestermiller said:
Yes, you're on the right track.

Oh my gosh, thank you so much guys!

X
2.7 * 9.6 = 25.92
2.1 * 2.9 = 6.09
1.5 * 0.9 = 1.35
SUM OF TORQUES = 33.39
DIVIDED BY SUM OF MASS = 13.4
33.39 / 13.4 = 2.5

Y
3.2 * 9.6 = 30.72
2.5 * 2.9 = 7.25
1.9 * 0.9 = 1.71
SUM OF TORQUES = 39.68
DIVIDED BY SUM OF MASS = 13.4
39.68 / 13.4 = 3
 
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