Recent content by flip290

The difference would then be zero?

So would it be Va=(8.99*109)((165*10-6)/1.76) plus the contribution from Vb therefore the answer would be V=1.7*106V?

The distance between the two is r=1.2m plus from the center of the sphere is 0.28m. Therefore the total distance would be 1.48m. If there are contributions from both charges am I not using the right equation?

So Va=k(q/r)=(8.99*109)((165*10-6)/1.48)=1.002*106? and the same for Vb?

This is where I am confused. Would you use the same equation but make r=1.20m?

Va=k(q/r)=(8.99*109)((165*10-6)/.28)=5.298*106 The potential for Vb would be the same but opposite. Is this correct?

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Thanks for the reply! I figured out that I actually had the right answer I was just confusing the units.

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