Recent content by Fontseeker

that's a typo, should be: $$\sqrt{\frac{2 * 1.6 * 10^{-17}}{9.11 * 10^{-31}}} = 5,936,739$$ I've dealt with energy and I get the same thing. Either way, it should work with velocity.

I am trying to solve the following problem: My attempt at the problem: $$m = 9.11 * 10^{-31}kg$$ $$q = 1.6 * 10^{-19} C$$ $$V_0 = \sqrt{\frac{2KE}{m}} = \sqrt{\frac{2 * 1.6 * 10^{-17}}{1.6 * 10^{-19}}} = 5,926,739 m/s$$ $$F_{net} = -F_{e} = ma$$ $$a = \frac{-F_{e}}{m} = ma$$ $$E =...

I was looking at a sphere that has a positive point charge at the center of a sphere with radius R. Now, I understand that the electric field is pointing outwards (in the direction of dA), so $$d\phi = EdA$$ However, I am told that since the magnitude electrical field is the same because the...

yes

thanks

If the y component will also change, then I would have several unknowns. I wouldn't know the position of particle 1, particle 4, and particle 2.

I have the following problem: So, I know the following: ##q_1 = -e## ##q_2 = -e## ##q_4 = -e## ##q_5 = e## ##e = 1.6*10^{-19}## ##k = 9*10^{9}## Now, I can get the current ##F_{net}## of particle 5 with this information: ##F_{net} = (F_{3} - F_{1})\hat i + (F_{2} + F_{4})\hat j## ##F_{1} = k...

sin(wt) = g / (Aw^2) and then replace w using frequency right?

sin(wt) = g / (Aw^2) right? Would you find w using conservation of energy or how would you find it?

I could use this equation, but I don't know w: a(t) = -Aw^2 * sin(wt)

It has to accelerate down at 9.8m/s^2

I am not really understanding your question

I would have to accelerate it down at g.

I know a(t) = -Aw^2 * sin(wt). Now, I am trying to find when the acceleration starts accelerating downward, so I can just set to 0 right?

Alright, so if I use conservation of energy: (1/2)mv^2 = mgh v = (2gh)^(1/2) The height would be h = (L^2 -x^2)^(1/2) so the Velocity = (2g * (L^2 -x^2)^(1/2))^(1/2) That doesn't show up on the answers.