Recent content by Fosheimdet
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Graduate Fourier transform equation question
How is it a total derivative though? Isn't ##\frac {\partial}{\partial x^j}## a partial derivative? Also, why can you make the assumption that the function goes to zero at infinity?- Fosheimdet
- Post #3
- Forum: Differential Equations
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Graduate Fourier transform equation question
In my QFT homework I was asked to prove that $$\int d^3x \int \frac{d^3k}{(2\pi)^3} e^{i\mathbf{k} \cdot (\mathbf{x} - \mathbf{y})} k_j f(\mathbf{x}) = i \frac{df}{dx_j}(\mathbf{y}) $$ Using ##\frac{\partial e^{i\mathbf{k} \cdot (\mathbf{x} - \mathbf{y})}}{\partial x^j} = i k_j e^{i\mathbf{k}...- Fosheimdet
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- Fourier Fourier transform Transform
- Replies: 3
- Forum: Differential Equations
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Graduate Understanding the Form Factor in Electron Scattering
I see. The ##\vec r'## will simply shift the origin of ## f(\vec r) = e^{i\vec q \cdot (\vec r-\vec r')} \frac{Q}{4\pi |\vec r-\vec r'|} ## and because the integral limits are ##-\infty## and ##+\infty##, the integral will be the same for every value of ##\vec r'##. We can therefore set ## \vec...- Fosheimdet
- Post #3
- Forum: High Energy, Nuclear, Particle Physics
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Graduate Understanding the Form Factor in Electron Scattering
I'm reading through Thomson's "Modern Particle Physics", and I've gotten stuck at a point in the derivation of the form factor for electron scattering in a static potential due to an extended charge distribution. It's just a mathematical "trick" i don't quite get. He goes from $$\int\int...- Fosheimdet
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- Form Hep Physics Scattering
- Replies: 2
- Forum: High Energy, Nuclear, Particle Physics
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Undergrad Possible measurements of z-component of angular momentum
I'm looking through an old exam, and don't quite understand the solution given for one of the problems. We have given a wavefunction g(\phi,\theta) = \sqrt{\frac{3}{8\pi}}(-cos(\theta) + isin(\theta)sin(\phi)) and are asked what possible measurements can be made of the z-component of the...- Fosheimdet
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- Angular Angular momentum Measurements Momentum
- Replies: 2
- Forum: Quantum Physics
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Graduate Compton scattering; conservation of momentum violated?
While reading the derivation of the formula \lambda' - \lambda = \frac{h}{ m_ec}(1-cos(\theta)) on Wikipedia, they point out that the momentum gained by the electron is larger than the momentum lost by the photon: $$ p_e=\frac{\sqrt{h^2(\nu-\nu')^2 +2h(\nu-\nu')m_ec^2}}{c} >...- Fosheimdet
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- Compton scattering Conservation Conservation of momentum Momentum Scattering
- Replies: 6
- Forum: Quantum Physics
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Graduate Stuck on the derivation of pV^gamma=c
T/V. You have my gratitude. I will now shed a tear for all the sleep this trivial thing has cost me.- Fosheimdet
- Post #5
- Forum: Thermodynamics
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Graduate Stuck on the derivation of pV^gamma=c
Yes, but p is constant as indicated by the subscript in \frac{\partial T }{\partial V}_p.- Fosheimdet
- Post #3
- Forum: Thermodynamics
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Graduate Stuck on the derivation of pV^gamma=c
I have been tearing my hair out for a while over a step in the proof of the relation pV^{\gamma}=constant. The textbook has assumed that we are dealing with an ideal gas undergoing an adiabatic process. Therefore dQ=0 and we get $$C_vdT + (c_p-c_V)\left(\frac{\partial T}{\partial...- Fosheimdet
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- Derivation Stuck
- Replies: 5
- Forum: Thermodynamics
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Graduate Harmonic Functions: Laplace's Equations & Analytic Functions
If $$f(z)=u(x,y)+iv(x,y)$$ is analytic in a domain D, then both u and v satisfy Laplace's equations $$\nabla^2 u=u_{xx} + u_{yy}=0$$ $$\nabla^2 v=v_{xx} + v_{yy}=0$$ and u and v are called harmonic functions. My question is whether or not this goes both ways. If you have two functions u...- Fosheimdet
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- Functions Harmonic
- Replies: 3
- Forum: Topology and Analysis
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Graduate Analyticity of the complex logarithm on the negative real axis
Thank you so much! Great explanation, made things allot clearer.- Fosheimdet
- Post #3
- Forum: Topology and Analysis
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Graduate Analyticity of the complex logarithm on the negative real axis
A theorem in my textbook states the following: For every n=0,±1, ±2, --- the formula ln z=Ln z ± 2nπi defines a function, which is analytic, except at 0 and on the negative real axis, and has the derivative (ln z)'=1/z. I don't understand why the logarithm isn't analytic for negative real...- Fosheimdet
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- Axis Complex Logarithm Negative
- Replies: 4
- Forum: Topology and Analysis
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Proving I-A is Invertible with A^m=0
Homework Statement Let A be a nxn matrix, and I the corresponding identity matrix, both in the real numbers ℝ. Assume that A^m=0 for a positive integer m. Show that I-A is an invertible matrix. Homework Equations The Attempt at a Solution- Fosheimdet
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- Algebra Linear Linear algebra Proof
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Momentum increased in electron-positron annihilation?
Yes they do collide head-on. And the Photons afterwards have opposite directions. But still the absolute value of the momentum has increased after the collision. Isn't this against the laws of physics?- Fosheimdet
- Post #3
- Forum: Introductory Physics Homework Help
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Momentum increased in electron-positron annihilation?
Homework Statement An electron and a positron is on a collision course. Both have a speed of 1,80*10^8 m/s. What are the frequencies of the two photons created after the electron and the positron has annihilated? Electron mass=positron mass= 9,11*10^-31 kg Homework Equations...- Fosheimdet
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- Annihilation Momentum
- Replies: 4
- Forum: Introductory Physics Homework Help