Recent content by Fused

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    Magnetisim Problem! Just need an Equation.

    Here's the problem: A proton follows a spiral path through a gas in a magnetic field of 0.010 T, perpendicular ot hte plane of the spiral. In two successive loops at points P and Q, the radii are 1.0 mm and 8.5 mm respectively. Calcualte hte hcnage in the kinetic energy of hte proton as it...
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    Point Charge Check?

    thanks docAl it should be invcos(43/55) to get 38.57 degrees.. Hm. but still not the right answer.
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    Point Charge Check?

    Point Charge Check!? Hi, I' did this problem but for some reason I'm not getting the right answer. If you could check to see where I made my mistake I'd really appreciate it. Thanks! The problem: A poitn charge (m=1 g) at the end of an insulating string of length 55 cm is observed to be...
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    Any Hints?

    I did that, but I don't know how to put the information into formulas
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    Any Hints?

    Nobody!?! Please help! I have a quiz this friday! I really need to know how to do these problems!!!
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    Any Hints?

    Any Hints!?!? I'm stuck on these 2 problems.. Any hints would be helpful! 1. What is the minimum work needed to push a 950-kg car 810m up along a 9 degree incline? a) ignore friction, b) assume the effective coefficient of a friction retarding the car is .25. This is what I did, but I...
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    Conservation of Energy Problem.

    At the highest point, vertical velocity is 0, and no, the horizontal velocity isn't affected... so then my final velocity would be zero, and y1 will be zero. This leaves me with 28.8-20 = (.40)(9.8)y2 y2 = 2.21 meters. Can anyone verify my answer?
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    Conservation of Energy Problem.

    Here's the problem: A .40 kg ball is thrown with a speed of 12m/s at an angle of 33 degrees. a) what is its speed at its highest point, and b) how high does it go? (Use conservat ionfo energy and ignore air resistance) I think I'm supposed to use the formula .5mvi^2 + mgy1 = .5mvf^2+mgy2 ...
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    Magnitude and direction for the total gravitational force

    So then,could I do this for the first force? Fm1m2 = (Gm1m2)/r^2 = G(9.5)(9.5)/(.601)^2 = 250.694G ?
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    Magnitude and direction for the total gravitational force

    Those unit vectors are unknowns, right?
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    Magnitude and direction for the total gravitational force

    I still don't quite understand. This is what I've done so far. I've drawn four spheres, one at each corner of the square. I've draw vectors from three spheres all pointing to the same one sphere. I've labeled the vectors A (the one pointing in the x direction) vector B, (pointing downwards...
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    Magnitude and direction for the total gravitational force

    I've done your step 1, I've drawn the vectors, three vectors one going from each of the three spheres to the same one sphere. Am I setting this up correctly? I know how to find the x and y components, but what would the resultant vector look like? I dont' understand how there can be one if all...
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    Magnitude and direction for the total gravitational force

    Please help me with the following problems!! Four 9.5 kg spheres are located at the corners of a squareof side .60m. calculate the magnitude and direction fo the total gravitational force exerted on one sphere by the other three. *I think I'm supposed to use the forumula : F= G(m1)(m2)/r^2...
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    What am I doing wrong?

    Yes, sorry about that... I actually got 1.5 m/s^2.
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