How can I solve these two physics problems involving work and springs?

Click For Summary
SUMMARY

The discussion focuses on solving two physics problems involving work and springs. The first problem calculates the minimum work required to push a 950-kg car 810 meters up a 9-degree incline, considering both frictionless and friction scenarios. The second problem involves a 65 kg trampoline artist jumping from a height, requiring calculations for landing speed and spring depression using the spring constant of 6.2 x 10^4 N/m. Key equations include work-energy principles and Newton's second law.

PREREQUISITES
  • Understanding of Newton's second law
  • Familiarity with work-energy principles
  • Knowledge of spring mechanics and Hooke's law
  • Ability to perform vector calculations in physics
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn about free body diagrams and their applications in problem-solving
  • Explore the concepts of potential and kinetic energy in physics
  • Review spring constant calculations and applications in real-world scenarios
USEFUL FOR

Students preparing for physics quizzes, educators teaching mechanics, and anyone interested in understanding the applications of work and energy in real-world scenarios.

Fused
Messages
29
Reaction score
0
Any Hints??

I'm stuck on these 2 problems.. Any hints would be helpful!

1. What is the minimum work needed to push a 950-kg car 810m up along a 9 degree incline? a) ignore friction, b) assume the effective coefficient of a friction retarding the car is .25.

This is what I did, but I don't think it's correct... :
A) W= Fdcost = mdcost = (950)(810cos9) = 7.6 * 10^5 J.
B) Wfr= Ffr*x*cos(180+9) = .25 * 810 *cos189 = -200 J

2. A 65 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 5 m/s. A) how fast is he going as he lands o nteh trampoline, 3 m below? b) if the trampoline behaves liek a sprign with spring stiffness constant 6.2 * 10 ^4 N/m how far does he depress it?
I got the a) part using .5mv^2 + mgy1 = .5mv^2 + mgy2
and found v= 9.15 m/s
b) I'm not sure which equation to use... I tried using .5mvi^2 + .5kx1^2 = .5mvf^2 + .5kx2^2 But I wasn't quite sure what to plug in, and when I tried all the different possibilities I did not get the corect answer.
 
Physics news on Phys.org
Nobody? Please help! I have a quiz this friday! I really need to know how to do these problems!
 
Fused do a Free body diagram for the body on the incline.
 
I did that, but I don't know how to put the information into formulas

Cyclovenom said:
Fused do a Free body diagram for the body on the i

ncline.
 
Use Newton's 2nd Law

\sum^{n}_{i=1} \vec{F}_{i} = m \vec{a}
 

Similar threads

Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
3
Views
3K
Replies
1
Views
3K
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
9
Views
3K
Replies
2
Views
16K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 13 ·
Replies
13
Views
3K