Recent content by Giiang

I got it. Thanks! So, a = -0.4t m/s^2 → v = ∫a dt = -0.2 t^2 + c and it was found in (i) that v(10) = 30 → 30 = - 0.2 10^2 +c → c = 50 The same goes with displacement.

this is the answer sheet:

Homework Statement A particle P starts from rest at a point O and moves in a straight line. P has acceleration 0.6t m s−2 at time t seconds after leaving O, until t = 10. (i) Find the velocity and displacement from O of P when t = 10. After t = 10, P has acceleration −0.4t m/s^2 until it...

Thank you. However, could you please elaborate? I'm still quite confused. Tcos25 is the horizontal component, why does it equal the vertical component?

Tension? knowing friction. I have the answer but need explanation :( Homework Statement A ring of mass 4 kg is attached to one end of a light string. The ring is threaded on a fixed horizontal rod and the string is pulled at an angle of 25◦ below the horizontal (see diagram). With a tension...