- #1
Giiang
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Homework Statement
A particle P starts from rest at a point O and moves in a straight line. P has acceleration 0.6t m s−2
at time t seconds after leaving O, until t = 10.
(i) Find the velocity and displacement from O of P when t = 10.
After t = 10, P has acceleration −0.4t m/s^2 until it comes to rest at a point A.
(ii) Find the distance OA.
Homework Equations
v = ∫a dt & s = ∫v dt
The Attempt at a Solution
For (i) v = ∫a dt = 0.3t^2 +c (c=0) = 0.3 x 10^2 = 30 m/s
s = ∫v dt = 0.1t^3 +c (c=0) = .1x10^3 = 100 m
But for (ii) I did the same thing...
a = -0.4t m/s^2
→ v = ∫a dt = -0.2 t^2 + c = -0.2 t^2 +30 because the initial velocity (when t=10s) is 30 m/s. However the answer said it should be 50 m/s? Could anyone explain me that please?
Also s=∫v dt = (-0.2t^3)/3 + 30t +100 (but the answer said -1000/3?)