Recent content by gillyr2

can anybody help?

Homework Statement A radio station is allowed to broadcast at an average power not to exceed 24 kW. If an electric field amplitude of 2.6×10−2 V/m is considered to be acceptable for receiving the radio transmission, estimate how many kilometers away you might be able to hear this station...

can someone help?

ok so it would be Q = (7*3500*10^-12) * 32V they want it in C. that gives 7.84*10^-7C which was my first answer but it is wrong.

Homework Statement A 3500 pF air-gap capacitor is connected to a 32 V battery. If a piece of mica fills the space between the plates, how much charge will flow from the battery? Homework Equations C= K*C_0 V= V_0/ K Q= C*V K of mica is 7 The Attempt at a Solution solved for...

ah. so its sqrt(3)/4 (1-y)^2

so the area is sqrt(3)/2 (1-y)^2? and i would just integrate that from 0 to 1 right?

The attempt at a solution[/b]Question: Find the volume of the solid whose base is the triangular region of the xy-plane with vertices (0,0),(1,0),(0,1) and whose cross sections perpendicular to the y-axis are equilateral triangles. I have the problem set up. just don't know how to get the...

Question: Find the volume of the solid whose base is the triangular region of the xy-plane with vertices (0,0),(1,0),(0,1) and whose cross sections perpendicular to the y-axis are equilateral triangles. I have the problem set up. just don't know how to get the cross sections of the...

ok. would this be correct? 3.0 grams / 63.5amu * 6.022 * 10^23 * 29 (electrons) = 8.2 *10^23 67 * 10^-6C / 1.6 * 10 ^ -19C = 4.2 * 10^14 (4.2 * 10^14)/(8.2 * 10^23) = 5.1*10^-10 Is this correct?

Homework Statement A 3.0-g copper penny has a positive charge of 67 mC. What fraction of its electrons has it lost? Homework Equations I don't think I am donig this right. i need guidanceThe Attempt at a Solution i take 3.0 grams * 63.5amu * 6.022 * 10^23 * 29 (electrons) = 3.3*10 ^ 27 67 *...

i have the same problem is the equation for acceleration a = (m2-m1)g/{(m1+m2)+.5m}

i can't get it. can someone help please/ i have w = v/R and alpha = w^2/2pheta

am i suppose to use alpha = w^2/2pheta

yes i have been looking for alpha but I am not sure how.