The problem involves calculating the fraction of electrons lost from a positively charged 3.0-g copper penny, which has a charge of 67 mC. The subject area includes concepts from electrostatics and atomic structure.
Some participants have provided alternative calculations and expressed uncertainty about the correctness of their results. There is a recognition of improved methods, but no consensus on the final answer has been reached.
Participants are working under the constraints of homework rules, which may limit the amount of guidance they can receive. There is also a focus on ensuring the calculations align with the properties of copper and its electrons.
gillyr2 said:Homework Statement
A 3.0-g copper penny has a positive charge of 67 mC.
What fraction of its electrons has it lost?
Homework Equations
I don't think I am donig this right. i need guidance
The Attempt at a Solution
i take 3.0 grams * 63.5amu * 6.022 * 10^23 * 29 (electrons) = 3.3*10 ^ 27
67 * 10^-6C / 1.6 * 10 ^ -19C = 4.2 * 10^14
3.3*10 ^ 27/4.2 * 10^14 = WRONG ANSWER. HELP!
gillyr2 said:ok. would this be correct?
3.0 grams / 63.5amu * 6.022 * 10^23 * 29 (electrons) = 8.2 *10^23
67 * 10^-6C / 1.6 * 10 ^ -19C = 4.2 * 10^14
(4.2 * 10^14)/(8.2 * 10^23) = 5.1*10^-10
Is this correct?