Recent content by GIM

Thank you, @vanhees71. What kind is the scale ##4\pi {f_\pi }##? Now, you changed my question into the relation between quark masses and pion decay constant. Then, again, what reasoning makes me ignore the masses? (For example, when I learned the pion decay, my professor used the formula...

Thank you, @RGevo. I just copied the value of ~200MeV from the literature. In many literatures(I've seen), which treat the chiral symmetry, most of them mention the similar statements. Is this really tricky?

Hello! Could anybody help me? My wondering seems so trivial, but I can't skip it. They say that since u and d quarks are much lighter than QCD scale(~200MeV), in reality we can consider the QCD Lagrangian has an approximate global chiral symmetry with respect to these two flavors. At first, it...

This is some kind of master course and I applied for PhD course in theoretical particle physics . If I fail in this interview, then I have to apply to the other university.

Hello! I am a diploma student at HEP section. I am going to have an interview for PhD within a week. I've finished the course and learned a lot about Lie algebra, quantum field theory, general relativity, standard model, etc. How can I review everything as soon as possible? For example, Mark...

Thank you, @samalkhaiat! I think this would be the best correct answer, even though I didn't understand it well. I will try to understand it along this direction. Thank you again.

I am sorry for my ignorance of latex. This was my equation. \begin{equation} \int {{\cal D}A\,{e^{iS\left[ A \right]}}} = \det \left( {\frac{{\delta G\left( {{A^\alpha }} \right)}}{{\delta \alpha }}} \right)\int {{\cal D}\alpha } \int {{\cal D}A\,{e^{iS\left[ A \right]}}\delta \left( {G\left(...

I am sorry, @andrewkirk. After insertion of the identity, it becomes \[\int {{\cal D}A\,{e^{iS\left[ A \right]}}} = \det \left( {\frac{{\delta G\left( {{A^\alpha }} \right)}}{{\delta \alpha }}} \right)\int {{\cal D}\alpha } \int {{\cal D}A\,{e^{iS\left[ A \right]}}\delta \left( {G\left(...

Can somebody help me? I am studying Faddeev-Popov trick, following the Peskin and Schroeder's QFT book, but I can't understand one thing. After they inserted the Faddeev-Popov identity, $$I = \int {{\cal D}\alpha \left( x \right)\delta \left( {G\left( {{A^\alpha }} \right)} \right)\det \left(...