Recent content by HellRyu

ok I got used the chain rule and got [(1/2x^{-1/2})/(1 + √x)] - [(3x^2)/(x^3)] then 1/[ (2√x) + 2x ] - 3/x How do I go from here to get the answer : (-6 -5√x)/[2x(1 + √x) ] ?

O.K. so I started doing the chain rule for the first one and got: (1/(1 + √x) )(1/(2√x) ) Is it right so far? EDIT: I did the second one and got: (1/(x^{3}) ) (3x^{2} )

Homework Statement Hi guys, I've got : y= ln ( (1 + √x) / x^{3}) 2. The attempt at a solution I honestly don't know where to go from here, I tried getting the ln of each of them. y = ln 1 +ln√x - ln x^{3} Am I doing it write? If not, how am I suppose to work this problem...

Ha! You guys are genius', thank you all so much! I figured it out.

O.K. I thought it was. I have: x/( (3x + 6)^{1/2} ) "f(x) / g(x)" I then get "g(x)( f' (x) ) -( f(x)( g'(x) ) ) " over "g(x)^{2} " I plug my f(x)'s and g(x)'s with their derivatives (3x + 6)^{1/2} (1) - (x(3x) ) over (3x + 6)^{3/2} Is this correct so far? Or did...

Hi, and thank you! :) I started using the quotient rule which got me stuck at: (-3x^{2} + 3x + 6)/ ( (3x + 6)^{3/2} )

Homework Statement I am doing my review for an exam Friday and the review shows only this: "find dy" x/( sqrt(3x + 6) ) The review gives me the answer which is: [(3x + 12)/2(3x + 6)^(3/2)]dx 2. The attempt at a solution I started out by re-writing the sqrt as " (3x + 6)^1/2 "...