When volume is reduced, pressure should increase and temperature should decrease according to these laws. So the reason for the temperature increase is only because of the work done on the gas molecules by the piston?
So when volume decreases, pressure increases according to Boyle's Gas Law and the ideal Gas Law. In other words, compressing gas into a smaller volume increases the vapor pressure. And also, According to Gay-Lussac's Law and ideal Gas Law, when pressure increases on a gas, temperature also...
I was confused about how a unit of energy such as BTU or joules can fit into the power equation where work is. I was confused whether thermal energy transfer is work. Some websites have suggested that it is not. These websites list the term "heat" as similar but different to work: which was...
Wouldn't "heat" imply a temperature difference? And when there is a temperature difference that suggests that thermal energy will start flowing from hot to cool areas? In other words: heat is an energy transfer of thermal energy. I was using "heat" in a similar manner to "work", in that I was...
From what I read: The Second Law of Thermodynamics allows work to be transformed fully into heat, but forbids heat to be totally converted into work. This is confusing because they are not totally interchangeable it seems.
"Heat" is a form of energy in transit: it has thermal energy as the...
Heat transfers from hot to cool areas. The sensation of cold is heat leaving our body. The sensation of warmth is heat entering our body. Temperature differences lead to an energy transfer of heat.
Work is mechanical energy moved in a direction and heat is the energy of random particles moving around? So you are saying that heat energy may be used in this equation, even though it says work?
So the formula for power is Power = work / time. There's two types of energy transfers: heat and work. How do you calculate the power of something using heat energy in BTU/hr when BTU isn't work?
Homework Statement
solve for t
Homework Equations
A = P (1+r)t + c[ ((1 + r)t+ 1 - (1 + r)) / r ]
The Attempt at a Solution
I've taken calc 1, but I've been away from math for years. I'm having trouble solving this for t
I see. So in middle red pipe, the fluid will increase in velocity which causes less pressure on water in that pipe in the system. That's kind of funny. At first I thought there would be more pressure on the smaller pipe, but it makes sense now.
So I've been discussing this problem with my plumber dad. I uploaded the picture.
I'm wondering if the pressure would change in the red pipe since the diameter decreases to 4 cm. Assume the 1st 10 cm pipe is full with water.
Question: If the home pressure is 517 kPa going through first pipe...
You are right. I converted both to MeV and it came out to KE = 0.029!
0.029 MeV ---> 4.646 x10-15 J
I calculate that the speed is 2.36 x 106 m/s.
However after using more sig fig digits the answer goes to 0 m/s. Maybe this is a relativistic problem that needs a different equation?
Homework Statement
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A proton and anti-proton are created by a photon with wavelength λ= 6.607×10−7 nm. What is the magnitude of the velocity of the newly created proton and anti-proton pair? Note, the mass of a proton/anti-proton is mp= 1.673×10-27 kg = 938.3M MeV/c2.
Homework Equations...