I Compressing gas with piston: reasons for temperature increase?

AI Thread Summary
When gas volume decreases, pressure increases according to Boyle's Law, while Gay-Lussac's Law indicates that increased pressure can lead to increased temperature. The temperature rise during compression is primarily due to the work done on gas molecules, which transfers kinetic energy and raises their energy levels. Rapid compression can produce more turbulence and pressure waves, resulting in greater energy transfer compared to slow compression. The ideal gas law encompasses these relationships, allowing for changes in pressure, volume, and temperature under different conditions. In adiabatic compression, both pressure and temperature increase significantly, demonstrating the complex interplay of these gas laws.
ikihi
Messages
81
Reaction score
2
So when volume decreases, pressure increases according to Boyle's Gas Law and the ideal Gas Law. In other words, compressing gas into a smaller volume increases the vapor pressure. And also, According to Gay-Lussac's Law and ideal Gas Law, when pressure increases on a gas, temperature also increases.

So am I correct in thinking that when a piston compresses gas ,the volume decreases; which increases pressure. Then this same higher pressure should make the temperature increase?

What are all of the sources behind higher pressure equaling higher temperature?

If temperature is proportional to the average kinetic energy of gas molecules then would just the fact of having more molecules in a smaller space increase the temperature due more kinetic collisions between the molecules and closer walls? Does it depend on how fast the volume is reduced by compression?

When you reduce a container volume by rapid compression, the temperature increases due to work on on the gas? This work transfers kinetic energy to gas molecules and extra energy should increase the temperature?
 
Last edited:
Science news on Phys.org
Boyle's law relates pressure and volume of a gas at constant temperature. Gay-Lussac's law relates the pressure and temperature at constant volume. You can't apply both of them at the same time. The ideal gas law generalises these laws (and Charles's law) to relate pressure, volume and temperature. Depending on the process, you can change any two of these properties while maintaining the third, or you can change all three at once. Thus it is not true to say, as a general rule, that reducing the volume increases the pressure and increases the temperature. It may do, it may not.
 
  • Like
Likes Dale and vanhees71
ikihi said:
When you reduce a container volume by rapid compression, the temperature increases due to work on on the gas? This work transfers kinetic energy to gas molecules and extra energy should increase the temperature?
Yes. Rapid compression or slow compression, both do work. Both result in gas molecules moving more energetically.

A compression rapid enough to produce pressure waves or turbulence in the gas would result in more work being done compared to a slow compression. Normally one would avoid such complications when trying to grasp the basics.
 
mjc123 said:
Boyle's law relates pressure and volume of a gas at constant temperature. Gay-Lussac's law relates the pressure and temperature at constant volume. You can't apply both of them at the same time. The ideal gas law generalises these laws (and Charles's law) to relate pressure, volume and temperature. Depending on the process, you can change any two of these properties while maintaining the third, or you can change all three at once. Thus it is not true to say, as a general rule, that reducing the volume increases the pressure and increases the temperature. It may do, it may not.
When volume is reduced, pressure should increase and temperature should decrease according to these laws. So the reason for the temperature increase is only because of the work done on the gas molecules by the piston?
 
ikihi said:
When volume is reduced, pressure should increase and temperature should decrease according to these laws.
No. Those laws do not require that.

Normally in an adiabatic compression, volume is reduced, pressure is increased and temperature is also increased while amount of substance remains unchanged.

The air in the cylinder gets hot and pressurized. You can inject the kerosene to make the Diesel cycle go.

If you are doing things adiabatically then the relevant ideal gas law is PV=nRT. The others are not applicable because you are not holding the required things constant.
 
Last edited:
You can compress the gas typically in two processes - adiabatic compression or isothermal compression. Boyle's law speak only about isothermal compression.
For Adiabatic process the equation is PV^(gamma) = Constant.

For example, you compress air at 1 bar and 300K temperature to a volume of 1/10. If it is isothermal compression you could get a pressure of 10 bar after compression with the same 300K temperature.

But, if it is Adiabatic compression using the Adiabatic equation, you would see that the pressure would be rather 25 bars.
Now, using the Universal gas law with volume 1/10, pressure 25 bars the new temperature would be around 750K. That is the difference.
 
I need to calculate the amount of water condensed from a DX cooling coil per hour given the size of the expansion coil (the total condensing surface area), the incoming air temperature, the amount of air flow from the fan, the BTU capacity of the compressor and the incoming air humidity. There are lots of condenser calculators around but they all need the air flow and incoming and outgoing humidity and then give a total volume of condensed water but I need more than that. The size of the...
Thread 'Why work is PdV and not (P+dP)dV in an isothermal process?'
Let's say we have a cylinder of volume V1 with a frictionless movable piston and some gas trapped inside with pressure P1 and temperature T1. On top of the piston lay some small pebbles that add weight and essentially create the pressure P1. Also the system is inside a reservoir of water that keeps its temperature constant at T1. The system is in equilibrium at V1, P1, T1. Now let's say i put another very small pebble on top of the piston (0,00001kg) and after some seconds the system...
Back
Top