Recent content by imatreyu

Oh, thank you so much! You really cleared it up for me.

Oh thank you! I totally forgot about that. Still though, I really don't understand what's going on in terms of the liquid's friction and work and energy in the system. What does the liquid friction work against?

Homework Statement A 0.75 sphere is dropped through a tall column of liquid. When the sphere has fallen a distance of 2.0 m, it is observed t have a velocity of 2.5 m/s. How much work was done by the frictional viscosity of the liquid? PLEASE EXPLAIN-- I really would like to understand this...

Homework Statement Two blocks with masses 1 kg and 4 kg, respectively, are moving on a horizontal frictional surface. The 1-kg block has a velocity of 12 m/s, and the 4-kg block is ahead of it, moving at 4m/s. The 4 kg block has a massless spring attached to the end facing the 1-kg block. The...

From my understanding, I already know Y from the problem? L= (Ydark * d)/ lambda(m+1/2) using .004 m for Ydark, .0003 m for d, 4.6e-7 for lambda When m= 0, L= 5.217... When m= 1, L=1.7391... L1-L2= 3.532 m Which is, unfortunately, not correct. (Correct answer is 2.61 m) Which is...

It is. However, I still don't have a value for m nor understand what it should be. Ydark= (wavelength*L)/d (m+1/2)

Thank you for your response, but I'm sorry...I still don't understand how that information translates into what I actually need to put into the equation. If I'm just using the m value for the second fringe, I have to put m=1 into the equation, which does not yield the correct answer.

Homework Statement Light of wavelength 460 nm falls on two slits spaced .3 mm apart. What is the required distance from the slits to a screen if the spacing between the first and second dark fringes is to be 4mm? Homework Equations Ydark= ((\lambdaL)/d)(m+1/2) Using ydark= .004 m d= .0003 m...

Actually. . . if someone could check my work: B= 4pi x 10^-7 * 1400 turns * 15 A = .0264 T flux = BA cos theta =.0264 T * (.0025 pi m^2) =2.0735 x 10^-4 T*m^2 Answer = 2.0735 x 10^-4 T*m^2

flux is BAcostheta.I'm confused on what to use for B. . .since there's no field created by the solenoid.

Sorry, the title is wrong. Should be "magnetic flux" of a single loop wire around a solenoid. Homework Statement A solenoid 4 cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. It is surrounded by a loop of wire 10 cm in diameter. The loop is positioned...

Homework Statement The observer in the figure shown below is positioned so thatthe far edge of the empty glass is just visible. When theglass is filled with water, the center of the bottom of the glassis just visible to the observer. Calculate the height H of theglass if its width W=4 cm...

Oh okay haha. . .P has to be half. . . Thank you :)

Homework Statement One mole of an ideal gas at an inital tempreature of 300K and pressure of 4 atm is carried through the following reversible cycle: a) It expands isothermally until its volume is doubled. b) It is compressed to its original volume at constant pressure. c) It is...

Oh! Why do I ignore the area?