Emf of a single loop wire around a solenoid

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Homework Help Overview

The discussion revolves around calculating the magnetic flux through a loop of wire surrounding a solenoid. The solenoid has specific dimensions and carries a current, while the loop is positioned perpendicular to the solenoid's axis. Participants are exploring the relationship between the solenoid's magnetic field and the flux through the loop.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the presence of an electromotive force (emf) in the loop given the negligible field outside the solenoid. There is also confusion regarding the definition of magnetic flux and the appropriate magnetic field to use in calculations.

Discussion Status

Some participants have provided definitions and attempted calculations related to magnetic flux, while others are verifying the existence of a magnetic field generated by the solenoid. The discussion reflects a mix of attempts to clarify concepts and check calculations without reaching a consensus.

Contextual Notes

Participants are grappling with the implications of the solenoid's magnetic field and the conditions under which the flux is being calculated. There is mention of specific values and equations, but the overall understanding of the problem remains in progress.

imatreyu
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Sorry, the title is wrong. Should be "magnetic flux" of a single loop wire around a solenoid.

Homework Statement



A solenoid 4 cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. It is surrounded by a loop of wire 10 cm in diameter. The loop is positioned perpendicular to and centered on the axis of the solenoid. Find the magnetic flux through the loop of wire. (The field outside of the solenoid is small enough to be negligible.)

Homework Equations



E= N*A*B*w*sinwt ?

The Attempt at a Solution



I don't know where to start...at all. How is there even an emf in the loop if the field around the solenoid is negligible?
 
Last edited:
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There's no EMF, but the question is asking for the flux. What's the definition of flux?
 
flux is BAcostheta.I'm confused on what to use for B. . .since there's no field created by the solenoid.
 
Are you sure the solenoid doesn't create a magnetic field?
 
Actually. . . if someone could check my work:

B= 4pi x 10^-7 * 1400 turns * 15 A
= .0264 T

flux = BA cos theta
=.0264 T * (.0025 pi m^2)
=2.0735 x 10^-4 T*m^2

Answer = 2.0735 x 10^-4 T*m^2
 
Last edited:

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