Recent content by james_rich
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High School Simple Quadratic Factor question
thanx i got that answer too, wasn't sure which way to work it out, the negative sign threw me a bit, the book is wrong then as i thought, they have 29/4 for their answer! thanx for ur help- james_rich
- Post #4
- Forum: General Math
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High School Simple Quadratic Factor question
Sorry, this sites changed a bit since i last came on, I've posted it in the wrong section- james_rich
- Post #2
- Forum: General Math
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High School Simple Quadratic Factor question
okay i need to solve the quadratic y = -x^2 + 5x + 6 and need to find the coordinates of the vertex of the curve by factorising y = -(x^2 - 5x - 5) y = -(x + 1)(x - 6) so when y = 0, x = -1 and x = 6 (that parts simple) .............. At the vertex x = (-1 + 6) / 2 = 5/2 (as...- james_rich
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- Quadratic
- Replies: 5
- Forum: General Math
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High School Simultaneous equation question
i think i see what i have done wrong the x = 3 is right but it is -x = -1! so x = 1 so to start again... as y = 2 - x y = 2 - 3 = -1 y = 2 - 1 = 1 so the co ordinates for the two roots of this curve is (-1, 3) and (1, 1) Thanx a lot, this is the answer in the book, easy...- james_rich
- Post #5
- Forum: General Math
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High School Simultaneous equation question
sorry, i still don't understand, i checked what i did, i can't see what's wrong with the bit highlighted! Can anyone elaborate?- james_rich
- Post #3
- Forum: General Math
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High School Simultaneous equation question
Hey just need my answer to be checked on this problem just to clarify x2 means x squared! Solve the following y = 2 - x x2 + 2xy = 3 Substitute equations x2 + 2x(2 - x) = 3 x2 + 4x - 2 x2 = 3 -x2 + 4x - 3 = 0 Factorising (-x + 1) (x - 3) = 0 so x = -1 and 3...- james_rich
- Thread
- Replies: 6
- Forum: General Math
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Solving Fractions with Roots: an Example
D'oh! that is so easy! I think i tried to over complicate it! My Brain hurts! I've stared at this piece of paper for the last 10mins! Thanx a lot, i can carry on now! Forgive the stupidity!- james_rich
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Solving Fractions with Roots: an Example
Hey having a bit of trouble with this question, not sure what to do! QUESTION - express the fraction in the form a + b rootc / d 3 + root24 / 2 + root6 ------------------------------------------ (3 + root24 / 2 + root 6) x (2 - root 6 / 2 - root 6) Simplifying gives (6 -...- james_rich
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- Example Fractions Roots
- Replies: 2
- Forum: Precalculus Mathematics Homework Help
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High School Quick linear equation question
Not sure, its 3am in Britain! I can barely concentrate on the clock, let alone do my math homework! i'll leave it in the capable hands of the smart people on this site, tho all looks good to me Bed for me!- james_rich
- Post #6
- Forum: Linear and Abstract Algebra
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High School Quick linear equation question
think ur reading into this a bit too much, its a really basic question, and i have the right answer (i just found out)- james_rich
- Post #4
- Forum: Linear and Abstract Algebra
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High School Quick linear equation question
Hey, its bin ages since i did any maths, and gotten a little rusty, am i doing this right when solving these equations? Find a 3/a+1 = 4/a (multiply a+1) 3 = (4a + 4)/a (multiply a) 3a = 4a + 4 (-4)...- james_rich
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- Linear Linear equation
- Replies: 8
- Forum: Linear and Abstract Algebra
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Internal Resistance and Circuits
okay... 6V = 4C + 4A 6V = 4C + B combining the equations together i get: B = 4 x A i can't seem to be able to get any values for either A or B, to be able to work out the current of C using Kirchoff's first law! Is this problem actually solveable?- james_rich
- Post #4
- Forum: Introductory Physics Homework Help
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Internal Resistance and Circuits
okay it didn't come out that great... current A is across the 2 ohm resistor, and 6V cell current B is across the 1.5V cell current C is the junction of A and C across the 4 ohm resistor. I kno i may have to use Kirchhoff's laws! but not sure how hope this helps if your as confused...- james_rich
- Post #2
- Forum: Introductory Physics Homework Help
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Internal Resistance and Circuits
Hey, I'm revising for my summer exams, and gotten stuck on this particluar question. _______ 6V ______2.0 ohms___ I I A I I I I I_____4.0...- james_rich
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- Circuits Internal Internal resistance Resistance
- Replies: 4
- Forum: Introductory Physics Homework Help
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Calculating GPE and Power for a Cable Car Ride
Hey just gettin a bit stuck on this question...i'll attempt to answer it, but it really doesn't look right to me. A cable car is used to carry people up a mountain. The mass of the car is 2000kg and it carries 80 people, of average mass 60kg. The vertical height traveled is 900m and the...- james_rich
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- Cable Car Gpe Power
- Replies: 2
- Forum: Introductory Physics Homework Help