Solving Fractions with Roots: an Example

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SUMMARY

The discussion centers on simplifying the expression (3 + √24) / (2 + √6) by rationalizing the denominator. The user correctly multiplies by the conjugate (2 - √6) to eliminate the radical in the denominator. The simplification process reveals that √144 equals 12, which is a crucial step in further reducing the expression. The user acknowledges initial confusion but ultimately clarifies their understanding of the simplification process.

PREREQUISITES
  • Understanding of rationalizing denominators in algebra
  • Familiarity with simplifying square roots
  • Knowledge of conjugates in mathematical expressions
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study techniques for rationalizing denominators in more complex fractions
  • Learn advanced square root simplification methods
  • Explore the properties of conjugates in algebra
  • Practice problems involving fractions with roots for mastery
USEFUL FOR

Students learning algebra, educators teaching rational expressions, and anyone seeking to improve their skills in simplifying fractions with roots.

james_rich
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Hey having a bit of trouble with this question, not sure what to do!

QUESTION - express the fraction in the form a + b rootc / d


3 + root24 / 2 + root6

------------------------------------------
(3 + root24 / 2 + root 6) x (2 - root 6 / 2 - root 6)

Simplifying gives

(6 - 3root6 + 2root24 - root144) / -2

(6 - 3root6 + 2 x 2root6 - root144) /-2

is this right so far? the problem i am having is simplifying the root144 to a root6 inequality!
 
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HINT: \sqrt {144} = 12
 
D'oh! that is so easy!

I think i tried to over complicate it! My Brain hurts! I've stared at this piece of paper for the last 10mins!

Thanx a lot, i can carry on now!

Forgive the stupidity!
 

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