Recent content by Jen2114

Thank you! , this really helped.

Ok, thanks! will do.

Oh ok this makes sense to me according to the product and quotient rule but the final solution given to us in class should be dPA/aPA = -dVL/VL + dNL/NL so maybe I just can't see it but I'm not sure if the result you showed me simplifies to this so I know what the solution should be but I'm not...

Ok so then -->1. d/VL(log(VL)) - d/NL(log(NL)) = 1/a*(d/K(log(K))) - 1/a*(d/PA(log(PA))) 2. dVL/VL - dNL/NL = -1/a*dPL/PL and since K is a constant the derivative is 0 so it this correct? Thanks.

Yes, but I am not sure how it works for a total derivative of an expression.

Yes, sorry so what I mean is log(K) and log(PA) are both multiplied by 1/a

So these are the steps I took 1. Divide both sides by PA --> PA(VL/NL)a = K --> (VL/NL)a = K/PA 2. Take log of both sides so a in exponent can be brought down --> log ( (VL/NL)a )= log(K/PA) --> a*log(VL/NL) = log((K/PA)) 3. Using log properties rewrite VL/NL and K/PA as differences to...

It should be the second one where only VL and NL are raised to exponent variable a. So, in that case is the result a[log(PA) + log(VL) - log(NL) = log (K) correct?

Thanks, so doing that I got the following: log(PA(VL/NL))a = log(K) --> a*log(PAVL/NL) = log (K) --> a[log(PA) + log(VL) - log(NL)] = log(K) using log properties for multiplication and division. Is this good so far?

Homework Statement For a single mechanical unit lung, assume that the relationship among pressure, volume, and number of moles of ideal gas in the ling is given by PA((VL)/(NL)a = K, where a = 1 and K is a constant. Derive the lowest-order (linear approximation to the relationship among changes...

Thank you ! I wasn't aware of this but now that I am it makes much more sense!

Homework Statement Hi, I am having trouble understanding how the B1 field as described by (3.48) in the image attached in MRI which is described as a linearly polarized field is decomposed into it's final two circularly polarized field as described by (3.49) in the image attached. Homework...

Hello, its been a while since I have taken linear algebra and I am having trouble understanding what a target vector is. I need to solve a system of linear equations in matrix form using back substitution and with different target vectors. I don't have a problem with back substitution, but I...

Ok thank you for your help

Homework Statement Construct a 3x3 matrix A and vectors b and c in R^3 so that Ax=b has a solution but Ax=c Homework EquationsThe Attempt at a Solution So I don't know where to start. I am not sure if the problem is asking me to create a matrix with real numbers or variables. What I do know is...