Matrix A and Vectors b & c in R^3: Solving Ax=b & Ax=c

In summary, to construct a 3x3 matrix A and vectors b and c in R^3 so that Ax=b has a solution but Ax=c, the matrix A should be singular and the vector b should be the only vector for which Ax=b has a solution. The simplest and most natural way to do this is to use a singular 3x3 matrix A and choose vector b accordingly.
  • #1
Jen2114
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Homework Statement


Construct a 3x3 matrix A and vectors b and c in R^3 so that Ax=b has a solution but Ax=c

Homework Equations

The Attempt at a Solution


So I don't know where to start. I am not sure if the problem is asking me to create a matrix with real numbers or variables. What I do know is that Ax=b has a solution if each row has a pivot , except the last column. So How would I use this to answer the question?
 
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  • #2
You left off a "doesn't" at the end of the question.

Taking that as read, the matrix has to be singular, otherwise we can just left-multiply both sides by ##A^{-1}## to find solutions for both equations.

What is the simplest, most monotonous, singular, 3 x 3 matrix you can think of?

If you call that matrix A, what is the only vector b for which A x = b will have a solution x?

I suspect that may not be the matrix they are looking for, but that's the simplest and most natural answer to the question as posed.
 
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  • #3
Ok thank you for your help
 

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