Matrix A and Vectors b & c in R^3: Solving Ax=b & Ax=c

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SUMMARY

The discussion revolves around constructing a singular 3x3 matrix A and vectors b and c in R^3 such that the equation Ax=b has a solution while Ax=c does not. It is established that for Ax=b to have a solution, matrix A must have a pivot in each row except the last column, indicating that A is singular. The simplest example provided is a singular matrix, which leads to a unique vector b that satisfies the equation, while vector c is chosen such that it does not correspond to any solution.

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  • Understanding of linear algebra concepts, specifically matrix operations.
  • Familiarity with the properties of singular matrices.
  • Knowledge of vector spaces and their dimensions.
  • Experience with solving linear equations in R^3.
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  • Study examples of linear transformations and their geometric interpretations.
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Students studying linear algebra, educators teaching matrix theory, and anyone interested in solving systems of linear equations in R^3.

Jen2114
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Homework Statement


Construct a 3x3 matrix A and vectors b and c in R^3 so that Ax=b has a solution but Ax=c

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The Attempt at a Solution


So I don't know where to start. I am not sure if the problem is asking me to create a matrix with real numbers or variables. What I do know is that Ax=b has a solution if each row has a pivot , except the last column. So How would I use this to answer the question?
 
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You left off a "doesn't" at the end of the question.

Taking that as read, the matrix has to be singular, otherwise we can just left-multiply both sides by ##A^{-1}## to find solutions for both equations.

What is the simplest, most monotonous, singular, 3 x 3 matrix you can think of?

If you call that matrix A, what is the only vector b for which A x = b will have a solution x?

I suspect that may not be the matrix they are looking for, but that's the simplest and most natural answer to the question as posed.
 
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Ok thank you for your help
 

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