Thanks for the pointer and after reviewing my notes a few more times, it has now become embarrassingly obvious. Much appreciated.
So, we have
dX = (\alpha - \beta X)dt + \delta dW
\frac{∂Y}{∂t} = 0, \frac{∂Y}{∂X} = 2x, \frac{∂^2Y}{∂X^2} = 2
therefore, from (slightly different...