Recent content by jill2040

Ah, the effective gravity won't do what I'm describing, it will only appear that way at one point, which is where I probably got my notion.

So as the sphere accelerates horizontally (and is not rotating I believe) the normal force as the body moves along the surface in the first quadrant is not just equal to m*9.8 m/s/s? I ask because the body starts at 45° and the question wants to know when it would leave the surface.

Homework Statement A small body is set on the surface of a smooth sphere at an angle of 45 degrees from the center. At this point the sphere is given a constant acceleration in the horizontal direction of 9.8 m/s/s. There is more in the question, but the goal is to find when the body will...

How would I go about that? I tried t=(4.7887 m/s * sin(34)/9.8 m/s^2 but that didn't seem to get me anywhere.

I used t=v/g and doubled it to account for the bearing coming back down.

1. A small steel ball bearing with a mass of 27.0 g is on a short compressed spring. When aimed vertically and suddenly released, the spring sends the bearing to a height of 1.17 m. Calculate the horizontal distance the ball would travel if the same spring were aimed 34.0° from the horizontal...