Projectile Motion Problem: Calculating Distance and Velocity

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Homework Help Overview

The discussion revolves around a projectile motion problem involving a steel ball bearing launched from a compressed spring. The original poster seeks to calculate the horizontal distance traveled when the spring is aimed at an angle of 34.0° from the horizontal, having already determined the height achieved when launched vertically.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to find the initial velocity and total time of motion, expressing confusion over their calculations. Participants question the method used to determine the total time of motion and suggest that the time of flight should be calculated specifically for the angled launch.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to approach the problem. There is an exploration of different interpretations regarding the calculation of time of flight and the use of equations of motion. No consensus has been reached yet.

Contextual Notes

The original poster mentions that they do not need answers but rather directions with concepts, indicating a desire for guidance without direct solutions. There is also a focus on ensuring the calculations account for the angle of launch.

jill2040
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1. A small steel ball bearing with a mass of 27.0 g is on a short compressed spring. When aimed vertically and suddenly released, the spring sends the bearing to a height of 1.17 m. Calculate the horizontal distance the ball would travel if the same spring were aimed 34.0° from the horizontal.



2. I've tried the whole problem from every direction I can think of but I keep getting it wrong. Can anyone tell me step by step what I would need to do? I don't need answers, just directions with concepts.



3. I assume the first thing I need to do is find the initial velocity. I found what the final velocity would be if the bearing was dropped from 1.17 m to be -4.7887 m/s. I found that number no matter what[ equation I used. From there, I found the total time of motion to be .9772 s. I multiplied the t times the initial v times cos(34) and got 3.88 m but the homework program still told me I was wrong. I'm missing something.
 
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Can you detail how you found your "total time of motion"?
 
I used t=v/g and doubled it to account for the bearing coming back down.
 
I think you'll want to calculate the time of flight for the case when the ball bearing is launched at an angle. Time of flight will vary with angle.
 
How would I go about that? I tried t=(4.7887 m/s * sin(34)/9.8 m/s^2 but that didn't seem to get me anywhere.
 
Go back to the general equation of motion for the y-component of the motion.

y = v*t - (1/2)gt^2

You have a velocity for the y-component, and the flight ends when y = 0. Solve for t.
 

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