Right, the total speed should be v^2 , not v . Then the square root makes it v .
Seperating the equation for \dot y ,
\dot y \, = \, v \, (1 \, - \, \frac{\ddot y}{g\,sin\theta}) .
As t -> \infty , \ddot y -> 0 because the block will be moving straight down the incline. This can't be...