1. The problem statement, all variables and given/known data Attached below 2. Relevant equations Emf = - [itex]\Delta[/itex][itex]\Phi[/itex] / [itex]\Delta[/itex]t emf = vBl; motional emf 3. The attempt at a solution In the two attached files, there are problems that ask for the direction of the induced current. I understand that the induced current flows in the direction that opposes the magnetic flux that created it. In the first file, [itex]\Delta[/itex][itex]\Phi[/itex] is negative because flux (BAcos[itex]\theta[/itex]) was smaller in the 2nd case than in the 1st. cos 0 > cos 60. The opposite direction of the induced current is up because [itex]\Delta[/itex][itex]\Phi[/itex] is negative But, how would I find out the direction of the current? FB = I l B sin[itex]\theta[/itex] We only know that we need magnetic flux and magnetic field to point upwards. Without the direction of FB, how can I use the right hand rule to find the direction of the induced current? I have the same problem with the problem shown in the second file. emf = vB l (memorized equation) We then need magnetic flux out of the page and the magnetic field to do so as well. Also, is motional emf the same as induced emf?