Recent content by joshmdmd

I'm not sure how much anyone is willing to pay to machine those LOL

rotating about the x y z axes make up the 4th 5th and 6th axis. it has nothing to do with the tool moving and the table moving.

nope. it has to be done without L'Hospital's rule, and we learn the taylor / maclaurin series next semester?. My attempts to rearrange it only get down to x on the bottom, can't seem to shake it out.

asymptotes :D

Homework Statement Find the following limit as x tends to zero (idk how to code this stuff properly so the lim is lim as x->0) lim (sinx-tanx)/x^3 Homework Equations lim(sinx)/x = 1 lim(cosx) = 1 lim(1-cosx)/x = 0 The Attempt at a Solution attempted to multiply by...

I would enjoy both equally. If I go to UofT then I figure I would either transfer to Mech if I don't like it, or double major, or get a masters. If I go to Ryerson then I'll get my BSc and then find work.

Im not basing my decision on an online poll, I have to look some stuff up and this could offer some information.

This is an outdated question. It would be simple to separate velocity and then work on vertical velocity at 1.2s. Then you can add the components back together to get the velocity.

I can't sit still without music. I just open up a huge trance set and do work. If I try to sit down and do stuff, I can only do it when I know it has immediate impact on my mark.. Assignments and Evaluations.

Ryerson: Mechanical Engineering BEng University of Toronto: Physics and its Applications Hons BSc Which would you pick?

cos(inversecos(4/21)) = 4/21 i know this is two years late and pretty useless but i have my test in a few days and I googled a question worded slightly different. Thanks, i know 7 now. 17. The vectors x = (-4,p,-2) and y = (-2,3,6) are such that inversecos(4/21) = theta, where theta is...

I have been assigned this question.. the answer according to my worksheet is given as 7.4E22kg I cannot get this answer by finding a through a=d/t^2, My attempt: Fnet=ma=Fg=Gmm/r^2 ma=Gmm/r^2 a=Gm/r^2 (r^2*a)/G = 3.631304348E22 (its half of the actual answer.. what am I doing wrong??)

https://www.physicsforums.com/showthread.php?t=380991 if you're still around on the forums..

A way to reduce impact would to be ideally move away from the merging car in the same direction so that less damage occurs.

Im just going to put out a guess.. Both tin cans are identical in shape so they both encode and decode the same way. The first one simply converts the sound into a vibration in the string, and the second cup converts it back.. An example of this could probably be sending and receiving radio...