Recent content by kee23

2.26*103kJ/kg? I don't get your question...

Homework Statement How much heat is required to convert 1.0 kg of water at 85°C to steam at 118°C? Homework Equations Q=mc(delta)T Qw+Qs=0? The Attempt at a Solution we know the m(water)=1.0kg and c(water)=4186J/kgC and T=85C so using Heat (Q) formula Q=mcT---...

yay I got it. thank you.

umm shouldn't final speed go first then initial speed go last on your solution? how do you get the kcal part? I'm not sure what to do from there Also I made mistake, initial speed should be 23.6m/s

hmm so speed not suppose to get subtracted? sorry, my algebra is my most weakest spot.

Homework Statement A 5850kg truck decelerates uniformly from 85.0km/h to 50.0 km/h. if 95.0% of the energy reduction is converted into heat, how many kilocalories are produced? Homework Equations kinetic energy (Ek)= 1/2mv2 1 Cal= 4.18J The Attempt at a Solution So first I...

my bad. the 3rd is 330rev. Umm I'm not quite follow. t

Homework Statement I had a physics lab and we found the 3 trials of revolution in 2 min then the result came as 1st=344rev 2nd=332rev 3rd=330rev (These numbers is from the calculation of Final (2min) - Initial start) Then it asked to find the average angular velocity for three of...

I think I got it. Thanks for help people :D

hmmm I don't know how to get rid of "k" when I have y=K76.73/145.52

umm I think so because the answer they left was in decimals so real answer is 0.214 I don't what they're saying from the question "if x decreases by 23.3% and z increases by 45.3%, by what factor does y change?"

umm so I did it as y=Kx3/z2 and so I got the value : y=K12649/2052.09. So do I replace the "y" with -23.3% and +45.3% then solve for "K"?

Homework Statement Given that y is directly proportional to the cube of x and inversly proportional to the square of z, if x decreases by 23.3% and z increases by 45.3%, by what factor does y change? Homework Equations Couldn't make a equation but I tried like this: y=K/x^3+1/z^2...

I got N2 as 429N. Do I add N1(1132.485N)? or subtract to get the other force? EDIT: Nevermind, I got it. I had the Total force calculation got wrong. Thank you!

Fpainter= (62.5kg*9.81m/s)= 613.125N Fsupply= (11.0kg*9.81m/s)= 107.91N Fstands= 45.0kg*9.81m/s) = 441.45N Total force Fpainter+Fsupply+Fstands= 1162.485N = N1+N2 Then 613.125N*1.35m+107.91*1.00m/4.50m= N2= 207.9175N N1+N2= 1132.485N+207.9175N= 1370N so am I got it right? I don't get it. Please...