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## Homework Statement

How much heat is required to convert 1.0 kg of water at 85°C to steam at 118°C?

## Homework Equations

Q=mc(delta)T

Qw+Qs=0?

## The Attempt at a Solution

we know the m(water)=1.0kg and c(water)=4186J/kgC and T=85C

so using Heat (Q) formula Q=mcT--- (1.0kg)(4186J/kgC)(85C)=306*10

^{5}

then from here where I got stuck because there is no mass for steam and I thought of finding the mass steam first, so can someone show me the step?