How much heat is required to convert 1.0 kg of water at 85°C to steam at 118°C?
The Attempt at a Solution
we know the m(water)=1.0kg and c(water)=4186J/kgC and T=85C
so using Heat (Q) formula Q=mcT--- (1.0kg)(4186J/kgC)(85C)=306*105
then from here where I got stuck because there is no mass for steam and I thought of finding the mass steam first, so can someone show me the step?