Recent content by Khamul

Hello everyone, as the thread title implies, I'm in a bit of a bind when it comes to understanding the Moment Distribution Method for displacement methods of analysis. In particular, I am having a lot of trouble in determining Stiffness Factors. I have attempted to browse my book and online...

Hello everyone, as the title suggests I'm in need of finding some specific vendors or catalogs for a few particular items needed in my design project. My University will be taking care of the bill, so while I would appreciate modest cost expenses, it would benefit my college to have some of...

Great! Thank you for clearing that up, I knew you had to transform the functions, I just wasn't sure on the rules of being able to. I was initially making it a lot more complicated than it actually was I suppose :) cheers!

Just a quick update on my progress; I found an inverse formula fitting the format (a)/((s+a)^2) = a*t*(e^-at) So, given this, and knowing I have a 1/6 on the top, would I be able to do something similar to this? f(t)= 1/6 * (L^-1) 1/((s+2)^2) * 2/2 Where I pull the 1/6 out in front of...

Hello everyone, I'm currently enrolled in Control Theory at my University, and part of the coursework requires differential equations; which wouldn't be a problem, if not for the fact it's been 2 years since I've taken D.E. Anyway, over the course of the problem I ran into this little function...

Hello everyone, I'm currently enrolled in Control Theory at my University, and part of the coursework requires differential equations; which wouldn't be a problem, if not for the fact it's been 2 years since I've taken D.E. Anyway, over the course of the problem I ran into this little function...

Homework Statement Boxes A and B are at rest on a conveyor belt that is initially at rest. The belt is suddenly started in an upward direction so that slipping occurs between the belt and the boxes. Knowing that the coefficients of kinetic friction between the belt and the boxes are (\muk)A =...

Aha! THAT'S the bugger I forgot. I kept thinking of the product rule, and how utterly insane it made this. This helps a bunch, thank you :)

Homework Statement r = 2/(2 - cos (\pi*t)) Homework Equations N/A The Attempt at a Solution Hello everyone, first I would just like to say (which is obvious since I'm asking :-p ) That it's been a long long time since I've had to do derivatives, hence my total cluelessness with...

Alright, I think I'm getting the hang of it a bit more. (Visualizing trigonometry has never been my strong point, as you may have noticed.) Thanks for the help, Tiny-Tim! Sleep well you sweet prince! :biggrin:

Hello, Tiny! Thank you for getting back to me so quickly! :smile: Well, I was able to finally through much head-mashing to figure out the answer, but I'm not exactly sure WHY it's the answer. To obtain what the answer was, the equation was manipulated as before, however it was the...

An instantaneous velocity vector is the quotient of the position vector over a change in time t, no? I still do not believe I am following what you are advising I do.. I am missing a part of the picture, I know, but you are asking the very same question that is making me have pause with this...

That sadly, is what I'm having difficulty deducing. I don't have time or distance, I'm not sure what the acceleration is. The initial velocity is 50 m/s, with a 25 degree angle with the horizontal..I do not have a final velocity to go with this, nor an area of distance traveled, nor a time...

Homework Statement A golfer hits a golf ball from point A with an initial velocity of 50 m/s at an angle of 25° with the horizontal. Determine the radius of curvature of the trajectory described by the ball (a) at point A, (b) at the highest point of the trajectory.Homework Equations p = V2/an...

Goood morning tiny-tim, thanks for getting around to helping me so early!:smile: Huh. Well hey, look at that! I learned something new about slopes, thank you! Also, thank you for steering me in the right direction :smile: I was burned out between this and thermodynamics by midnight last night!