(Structural Analysis) Moment Distribution Method: Help?

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SUMMARY

The discussion centers on the Moment Distribution Method, specifically the determination of stiffness factors in structural analysis. The user expresses confusion over conflicting information regarding stiffness factors, K, with references to a PDF that states K=4EI/L for fixed ends and K(ab)=3EI/L for other conditions. Two approaches are suggested: using 4EI/L for all members, which requires multiple moment carry-overs, or employing a modified stiffness method that simplifies the process by using 3EI/L for spans with pins. The conversation highlights the importance of understanding symmetry and anti-symmetry in applying these factors effectively.

PREREQUISITES
  • Understanding of the Moment Distribution Method in structural analysis
  • Familiarity with stiffness factors and their calculations (K=4EI/L, K=3EI/L)
  • Knowledge of structural behavior under fixed and pinned conditions
  • Basic principles of symmetry and anti-symmetry in beams
NEXT STEPS
  • Research the application of the Moment Distribution Method in complex beam systems
  • Study the differences between fixed and pinned support conditions in structural analysis
  • Learn about the implications of symmetry and anti-symmetry on stiffness factors
  • Explore advanced texts on structural analysis, such as "Elementary Theory of Structures" by Hsieh and Mau or Hibbeler's works
USEFUL FOR

Civil engineers, structural analysts, and students studying structural mechanics who seek to deepen their understanding of the Moment Distribution Method and its practical applications in beam analysis.

Khamul
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Hello everyone, as the thread title implies, I'm in a bit of a bind when it comes to understanding the Moment Distribution Method for displacement methods of analysis.

In particular, I am having a lot of trouble in determining Stiffness Factors. I have attempted to browse my book and online for clarification, but I feel like every source I look at contradicts the other.

For example...page two and page three of this pdf:
http://www.sut.ac.th/engineering/civil/courseonline/430332/pdf/04_MomentDistribution.pdf

It states that if the far end member is fixed, then the stiffness factor, K, is K=4EI/L. Okay.
But page 4 of this pdf then goes on to state that K(ab) = 3EI/L, even though the far end D on this is fixed.

Could someone please help me make sense of this? :(
 
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1) You can always use 4EI/L for all members. If you choose to do this, then the moment distribution process will be a bit longer and you will have to repeatedly "carry-over" the moments back and forth until they become small enough ("small enough" is based on your own judgement).

2) Alternatively, you can use the "modified stiffness" moment distribution method. In this case, one way to do it for your beam is to observe that there is a pin at the end of one of the spans. This means that you can choose to use 3EI/L for that span. Leave the other spans as 4EI/L. The advantage, in general, of using a "modified stiffness" is that you only "carry-over" the moments one-time.

It is unfortunate that the beam in question is not solved by either method 1) or 2) in your attached file, even though they mention both of these methods on pg 2, pg 3, as you mentioned (or did I just miss it?). Nevertheless, it appears that they solve a variety of problems later on...

Note the beam on pg 7, for example -- Here, they use a modified stiffness factor for all 3 spans. They get the 2EI/L by observing "symmetry" in the first span. This problem is solved in one step, but it is a simpler problem. Later on, in other examples, 6EI/L pops up, which is the modified stiffness factor for "anti-symmetry."


I've attached my own notes on the subject. It's only 8 pages, and would probably be worth your time if you are still "in a bind." It is adapted from "Elementary Theory of Structures" by Hsieh and Mau. Back when I learned this stuff that was the best text on the subject. I think Hibbeler has since gotten in on the action.
 

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