Recent content by kirby2

and the other answers are wrong, correct?

fdsfds sdfs

3.1E-6 is from series. so you add them by 1/C and the answer is 1/c. so for the first one i did 1/8.6E-6 + 1/4.8E-6 = 1/C where C is 3.1E-6 4.1E-6 is also from series. i did 1/6.2E-6 + 1/11.8E-6 = 1/C where C is 4.1E-6. 7.6E-6 is parallel so you just add them. i added 4.1E-6 to 3.5E-6

final capacitance = 1.48E-5 F. i combined 3.1E-6, 4.1E-6 and 7.6E-6

i did this in three steps. i found C from the first two as a series. then i found c from the top two as a series. then i used my answer from the top two and the lower capacitator as a parallel network. so in the last calculation i did 4E-6. AH! there is my mistake. before i had my old...

3.1e-6 + 4e-6 + 4.9e-6

ok. adding all the Cs gives me 1.2E-5. i plugged this into the formula U=.5CV^2. for v i used 12 and solved for u

my bad. i don't know what i did wrong, but i redid it and got u=8.64E-4.

i then got a total capatance of 1.21E-5 F and a total energy of 0.0027 J

i re-did it and got 4E-6. is this right?

For the capacitor network shown in the figure, the potential difference across ab is 12V. Find (a) the total energy stored in this network and (b) the energy stored in the 4.8 uF capacitor. figure: http://i.imgur.com/Wxbuu.png ATTEMPT: PART A: i first did the leftmost 2 capacitors...

A point charge 6.50 nC is at the center of a cube with sides of length 0.260 m. PART A: What is the electric flux through the surface of the cube? PART B: What is the electric flux through one of the six faces of the cube? ATTEMPT: A) Total flux enclosed by the cube = Q / eo...

A proton is traveling horizontally to the right at 4.20×106 m/s. Find (a)the magnitude and (b) direction (counterclockwise from the left direction) of the weakest electric field that can bring the proton uniformly to rest over a distance of 3.40 cm. Part C: How much time does it take the...

my last response's answer is in C/m^3. (2.387E-6) is this one right?

yes. and the sides are positive. thank you