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Potential and field at two electric plates

  1. Feb 9, 2012 #1
    fdsfds sdfs
     
    Last edited: Feb 9, 2012
  2. jcsd
  3. Feb 9, 2012 #2

    Delphi51

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    Yes on both A and C. My explanation for A would be that work needs to be done to push a positive test charge from B to A against the force of the electric field. Your V=kq/r is obscure (unrelated to this question) because it is the absolute potential or work/charge for moving a charge from infinite distance into a position that is distance r away from charge q. It does tell you that the potential midway between the positive and negative plates is zero, though.
     
  4. Feb 9, 2012 #3
    and the other answers are wrong, correct?
     
  5. Feb 9, 2012 #4

    Delphi51

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    Correct.
     
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