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kirby2
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fdsfds sdfs
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Potential and field at two electric plates
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The discussion centers on the electric potential and field between two plates, confirming that work is required to move a positive test charge against the electric field from one plate to another. The equation V=kq/r is deemed irrelevant to the question, as it pertains to absolute potential rather than the specific scenario discussed. It is noted that the potential at the midpoint between the positive and negative plates is zero. The participants agree that the other answers provided are incorrect. Overall, the conversation emphasizes the relationship between electric potential, work, and the behavior of charges in an electric field.
The answer is (B) but I don't really understand why.
Based on formula of Young Modulus:
$$x=\frac{FL}{AE}$$
The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A##
I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...