Recent content by Kizaru

  1. K

    Implementation of a 4 variable function using two 4-1 MUX (to get an 8-1 MUX)

    Homework Statement Implement F(w, x, y, z) with an 8-to-1 multiplexer which is constructed from two 4-to-1 multiplexers. The control signals must be w, y, and z.Homework Equations F(w, x, y, z) = \sum m(0, 3, 6, 8, 10, 13) The Attempt at a Solution I believe x is used for the strobes to...
  2. K

    Converting a boolean expression into simplest product of sums

    Algebraically. But I just got the answer. I used a K-Map to see the answer and then made a simplification (removing the ABD' term by showing it is irrelevant using perfect induction). It was cake after that. I still appreciate the response though.
  3. K

    Converting a boolean expression into simplest product of sums

    Homework Statement Given F = (A'+B')[ABD' + A'C + A'BD], simplify into a simplest product of sums.Homework Equations The Attempt at a Solution Multiplying through gives me A'BD + A'C. I have tried expanding, adding consensus terms, but I'm not sure how to take it from there. Additionally, I...
  4. K

    Suppose a, b, c are real numbers and x,y,z>=0. Prove the following inequality

    Err yes, it should be x,y,z > 0. I haven't touched it since last night, so I'll see where I can get with the simpler problem today.
  5. K

    Suppose a, b, c are real numbers and x,y,z>=0. Prove the following inequality

    Homework Statement Suppose that a, b, c are real numbers and x, y, z >= 0. Prove that \frac{a^2}{x} + \frac{b^2}{y} + \frac{c^2}{z} \geq \frac{ (a+b+c)^2}{x+y+z}Homework Equations Cauchy-Schwarz and Arithmetic Geometric Mean inequalities.The Attempt at a Solution I wasn't really sure how to...
  6. K

    Intro to analysis proof first and second derivatives and mean value theorem

    What does f''(x) indicate about f(x)? When you see this, you will realize how the f'(c)=0 comes into play.
  7. K

    Bacterial Growth: Solving an ODE for Population Size

    Look at your ODE. It's missing something. The population _DOUBLES_ every 40 minutes. You seem to have forgotten about this fact. A suggestion: convert to hours at the very end.
  8. K

    Modeling with First Order Differential Equation

    Er yes, I got them mixed up. He probably caught it though.
  9. K

    Modeling with First Order Differential Equation

    It's clear the rate of salt entering the tank is 0, correct? The rate leaving depends on the concentration and the rate of solution leaving, correct? The concentration depends on the amount of salt and the amount of solution. What is the amount of solution (aka the volume of the tank)...
  10. K

    Modeling with First Order Differential Equation

    Try to model a diff eq for the volume of the tank at all times. You will figure out the volume from there, and then you can use that in dQ/dt
  11. K

    Modeling with First Order Differential Equation

    Q = amount of salt in tank. dQ/dt has units of mass/time right? So the "rate in" and "rate out" must also have these same units. Now, pure water enters the tank at the rate of 12L/min. That rate in contains no salt, therefore rate in = 0. The rate out is tricky. The rate of salt leaving is...
  12. K

    Solve ab+cd Given a^2+b^2=c^2+d^2=1 and ac+bd=0

    boboYO, that is a very interesting solution. Thank you!
  13. K

    Solve ab+cd Given a^2+b^2=c^2+d^2=1 and ac+bd=0

    OH, I see my mistake. I had a^2 = -\left(\frac{bd}{c}\right)^2 Which is why I had the 2 inside the parentheses. And from there we get a^2 = d^2 as well, and since one must be negative to satisfy ac+bd= 0 blah blah ab+cd = 0. Thank you very much!
  14. K

    Solve ab+cd Given a^2+b^2=c^2+d^2=1 and ac+bd=0

    I tried that approach earlier and obtained c^{2}(2-\frac{1}{b^{2}}) = 1 I was unable to manipulate it any further into something meaningful. It feels like I am missing something from this approach as well.
  15. K

    Solve ab+cd Given a^2+b^2=c^2+d^2=1 and ac+bd=0

    Homework Statement Suppose that a, b, c, d are real numbers such that a^2 + b^2 = c^2 + d^2 = 1 and ac + bd = 0. What is ab + cd? Homework Equations a^{2} + b^{2} = c^{2} + d^{2} = 1 ac + bd = 0 The Attempt at a Solution Clearly, ac = -bd. I know the solution is 0, but I am having trouble...
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