Recent content by knapklara
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Graph Reading: Get it Right the First Time!
Or I'd maybe even put it like this based on your explanation. Is it correct that maximum velocity is then found in the middle of the steep, did I get that right?- knapklara
- Post #14
- Forum: Introductory Physics Homework Help
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Graph Reading: Get it Right the First Time!
Thank you very much for your explanation, you explained it wonderfully for someone who is not too much of a "physicist". Now I would say that the second graph is also done correctly as it is, without my red marks. It confused me a little because I was looking at a graph of a sprinter and there...- knapklara
- Post #13
- Forum: Introductory Physics Homework Help
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Graph Reading: Get it Right the First Time!
I know how to read the basics from a graph such as what's the velocity at x time and so on... What do you mean exactly by how those graphs work?- knapklara
- Post #9
- Forum: Introductory Physics Homework Help
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Graph Reading: Get it Right the First Time!
So where would acceleration be zero or close to zero then reading the first graph?- knapklara
- Post #7
- Forum: Introductory Physics Homework Help
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Graph Reading: Get it Right the First Time!
I appreciate your feedback but I'm afraid it's too complicated for me. Pic 1 Where there's velocity increasing, I would say that there's acceleration and just before the velocity starts decreasing, I'd say acceleration is zero, that's also where it is marked. Pic 2 Since the object starts moving...- knapklara
- Post #5
- Forum: Introductory Physics Homework Help
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Graph Reading: Get it Right the First Time!
I'm fairly certain that the first one is marked correctly. Should the second one be where there are red marks or is it correct as it was marked previously? Any advice with graph reading?- knapklara
- Thread
- Graph Reading Time
- Replies: 16
- Forum: Introductory Physics Homework Help
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Gymnastics max torque on the High Bar
I guess I'm meant to observe the athlete as a lever. I'm not sure how to give a better explanation since English is not my first language. Isn't it the biggest torque at about 90° angle if we consider gravity in the first half of the motion, kind of similar as when doing a biceps curl?- knapklara
- Post #11
- Forum: Introductory Physics Homework Help
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Gymnastics max torque on the High Bar
Of course, I haven't given enough detail. My question would be the biggest torque on the athlete. Do I make sense?- knapklara
- Post #5
- Forum: Introductory Physics Homework Help
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Gymnastics max torque on the High Bar
- knapklara
- Thread
- Max Torque
- Replies: 11
- Forum: Introductory Physics Homework Help
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Calculations for a Hammer Throw Event
OK, so after a little thinking I came up with this. Thank you everyone for your input!- knapklara
- Post #5
- Forum: Introductory Physics Homework Help
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Calculations for a Hammer Throw Event
I'm already confused by the terms circular, angular and radial. I've read the definitions but I'm still confused. What is the difference? Is ω the right symbol for frequency that I used? Any tips much appreciated!- knapklara
- Thread
- Calculations
- Replies: 9
- Forum: Introductory Physics Homework Help
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Simple kinematics question -- Riding a bicycle race in two different gears
Thank you very much for your perspective, much appreciated!- knapklara
- Post #13
- Forum: Introductory Physics Homework Help
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Simple kinematics question -- Riding a bicycle race in two different gears
All right, I'd kindly ask you for a comment. I knew all along that it was going to be quite simple and thank you for bearing with me! You pointed the obvious!- knapklara
- Post #10
- Forum: Introductory Physics Homework Help
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Simple kinematics question -- Riding a bicycle race in two different gears
Allright, that makes more sense, but I still don't know what to do with two unknown variables. Please forgive my ignorance.- knapklara
- Post #8
- Forum: Introductory Physics Homework Help
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Simple kinematics question -- Riding a bicycle race in two different gears
I thought about getting t2 from t1, but that still doesn't help one bit. I know the answer is right in front of me, but I just don't see it.- knapklara
- Post #5
- Forum: Introductory Physics Homework Help