Recent content by ladolce

Hey guys, I know how to do torque and forces for an object in equilibrium...but how do I know whether a torque is clockwise or counterclockwise?

Homework Statement The speed of a transverse wave on a string is 420 m/s, and the wavelength is 0.14 m. The amplitude of the wave is 1.5 mm. How much time is required for a particle of the string to move through a total distance of 1.0 km? Homework Equations λ x υ= v The Attempt at...

thanks! i always make dumb mistakes like that haha..

Simple Harmonic Motion-Help Please :) Homework Statement A loundspeaker diaphragm is producing a sound for 1.5 s by moving back and forth in a simple harmonic motion. The angular frequency of the motion is 8.50 104 rad/s. How many times does the diaphragm move back and forth? ________...

I agree, I'm finding it impossible to find a and b! I wanted to use the diagonal also, but I only know the large diagonal is the sq.root of 2 and it has a correlation to the sq.root of a squared + b squared...there arent any numbers to use though!

Homework Statement A rotational axis is directed perpendicular to the plane of a square and is located as shown in the drawing. Two forces, 1 and 2, are applied to diagonally opposite corners, and act along the sides of the square, first as shown in part a and then as shown in part b of the...

thanks i got the problem right after i typed it though =)

Homework Statement A person is riding a bicycle, and its wheels have an angular velocity of +19.5 rad/s. Then, the brakes are applied and the bike is brought to a uniform stop. During braking, the angular displacement of each wheel is +11.5 revolutions. (a) How much time does it take for...

haha...my uncle's from malawi. and yeah that has happened a lot of me and this bad system of online homework

that's what i hadput first but it said that was wrong... :( then i tried the 3 digit sig figs one and that worked..it always like the 3 digit sigfig answers better haha...

Wow, that's right. Thank you so much for your time once again!

Ok, I did it again and got y=(0)-(4.57 squared)/(2)(-9.8) and i got -1.066m would that be what you got?

I keep getting really small answers. Like, wouldn't I just do 4.57m/s=x/.018sec?

Oh, in the problem it says : "Assume that the only force acting on him during the collision is that due to the ground." so that's all i have to worry about. i have the right velocity as 4.57 m/s then...i don't know what to do next however.

what could i do next?