Simple Harmonic Motion- How Many Times Does the Diaphragm Move Back and Forth?

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SUMMARY

The discussion centers on calculating the number of cycles a loudspeaker diaphragm completes during 1.5 seconds of simple harmonic motion, given an angular frequency of 85,000 rad/s. The correct calculation involves determining the period (T) using the formula T = 2π/ω, resulting in T = 0.00007392 seconds. The frequency (f) is then calculated as f = 1/T, yielding approximately 13,528.139 cycles per second. Multiplying the frequency by the time duration of 1.5 seconds gives the correct number of cycles as 20,292.209, not 200,292.209 as initially miscalculated.

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Simple Harmonic Motion-Help Please :)

Homework Statement



A loundspeaker diaphragm is producing a sound for 1.5 s by moving back and forth in a simple harmonic motion. The angular frequency of the motion is 8.50 104 rad/s. How many times does the diaphragm move back and forth?

________ times

Homework Equations



ang.freq.=2pi/T

f=1/T

The Attempt at a Solution



Ok, so I plugged in w=85000rad/s and t=1.5s and got T=0.00007392 and f=13528.139 cycles/sec and

multiplied that f i got by 1.5 sec to get 200292.209 cycles which is wrong..

I don't know what i did wrong...can someone help?
 
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Everything looks right, except f * 1.5s = 20292.209 not 200292.209
 
thanks! i always make dumb mistakes like that haha..
 

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