Angular Velocity & Angular Acceleration

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SUMMARY

The discussion centers on calculating the time it takes for a bicycle to come to rest and the angular acceleration of its wheels after applying brakes. The initial angular velocity is +19.5 rad/s, and the angular displacement during braking is +11.5 revolutions, equivalent to 72.26 radians. The correct approach involves using the equation for angular displacement in uniformly accelerated motion, specifically the formula Δθ = ω₀t + (1/2)αt², to find the time and angular acceleration accurately.

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Homework Statement



A person is riding a bicycle, and its wheels have an angular velocity of +19.5 rad/s. Then, the brakes are applied and the bike is brought to a uniform stop. During braking, the angular displacement of each wheel is +11.5 revolutions.

(a) How much time does it take for the bike to come to rest?

(b) What is the angular acceleration of each wheel?

Homework Equations



avg ang. v=ang. x/t

avg ang. a=change in ang. v / t

The Attempt at a Solution



I plugged in and got...

delta theta=11.5 x 2pi=72.26 radians

and

72.26rad/(t) = 19.5

and so t=3.7 or 3.706 or 3.71 and all those are wrong... I don't know what i did wrong.
 
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You are treating this as problem with uniform angular velocity. Clearly that's not true since the bike is slowing down. You need the analog of x(t)=x0+v0*t+(1/2)*a*t^2. Remember linear motion?
 
thanks i got the problem right after i typed it though =)
 

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