Recent content by lorka150

i chose it because i know that metals + non-metals are ionic... and because they were both non-metals, it made me feel that way. also, i knew that ionic compounds were metal + polyatomic (and that wasn't that, either). that was my assumption. i just like to make sure i didn't miss something, as...

Thanks for the link. I do not understand it, but thank you for your help.

Thanks for the help so far, Geoff. I am only supposed to list two equivalent (I assume that might be the key word there) resonance forms. it's from first year university chemistry - just very out of my element. ... O ...// O - C ...\ ... O - H ...O .../ O - C ...\\ ...O -H...

Hi Geoff I explained my reasoning in the message above you. I thought that the highest lattice and shortest bonds correspond, and I know that as you move up and to the right that they are at the strongest - therefore because F is the farthest and Na is higher than K, I chose NaF. For the...

Thanks Geoff... In that case, I'm quite confused.

I did, sorry. I just didn't type it all. I read through the trends, and just want to make sure I interpreted them correctly. I was under the impression tha the shorter bonds and highest lattice energy would be the same, because the increased lattice = stronger bonds, and the strong bonds are a...

hi Steve, thanks. I re-checked my answer and realize I think I read the question wrong... Two lone pairs, meaning four all together (I was interpreting it like two, not two pairs) if that makes sense. Then I think it's XeF4.

I have to figure out which has two lone pairs on the central atom between PCl3, ICl4^+, CH3I, XeF4, PCl6^-. Is it PCl3? I think I did it right but I am not sure. Thank you.

Are two equivalent resonance forms HCO3^- like this? ... O ...// O - C ...\ ... O - H ...O - H .../ O - C ...\\ ...O Both structures have brackets and a -. Also, each O on the left has six dots, the O on the double bond has four, and the O on the H has four as well...

Is S2Cl2 covalent?

Out of KF, NaF, and RbCl, does NaF have the shortest ionic bonds as well as highest lattice energy, and RbCl have the lowest melting point? Thanks

are these correct? i always get confused with the rules for the end of the order: N^3- >> [Ne] Tl^3+ >> [Xe]4f14 3d10 Fe^3+ >> [Ar]3d5

Thank you for your help with this. So I divided 2.9979x10^8 m/s by 5.76 x 10^-7 m to get nu= 5.20 x 10 ^14 s^-1 Then for the second part (what is the energy in J of one photon of the raditon, I would still multiply 5.20 x 10 ^14 s^-1 by 6.6256 x 10 ^-34 J.sec, and then I would get 3.45 x...

I went over them with the table, and it looks like Set 2 is the only one that is not valid.

astronuc, thanks. so for the first one, instead of using 576.3nm, I would then multiply that by 10^-9m/1nm, so I get 5.76 x 10-7?