Which molecule has two lone pairs on the central atom?

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Discussion Overview

The discussion revolves around identifying which molecule among PCl3, ICl4+, CH3I, XeF4, and PCl6- has two lone pairs on the central atom. Participants explore the molecular structures and bonding characteristics to determine the correct answer.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests PCl3 as the molecule with two lone pairs, reasoning that phosphorus has three bonding electrons and two unshared electrons.
  • Another participant agrees with the initial assessment of PCl3 but later realizes that the question refers to two pairs of lone electrons, leading them to reconsider XeF4 as the correct answer.
  • A participant mentions that PCl3 has only one lone pair and rules it out as a possibility.
  • It is noted that CH3I cannot be the correct answer due to carbon's adherence to the octet rule.
  • Participants are encouraged to draw Lewis structures for the remaining options to clarify their configurations, with one noting that one of the molecules is square planar due to having two lone pairs.

Areas of Agreement / Disagreement

There is no consensus on which molecule has two lone pairs. Participants express differing views on PCl3 and XeF4, and the discussion remains unresolved regarding the correct answer.

Contextual Notes

Participants acknowledge potential misunderstandings in interpreting the question about lone pairs and the necessity of drawing Lewis structures to clarify molecular geometries.

lorka150
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I have to figure out which has two lone pairs on the central atom between PCl3, ICl4^+, CH3I, XeF4, PCl6^-.

Is it PCl3? I think I did it right but I am not sure.
Thank you.
 
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Think you are correct. The three 3p3 electrons of P should be bonded to the three Cls, each one forming single bonds. That leaves the pair of 3s2 electons unshared. Haven't even looked at the other choices, since I feel PCl3 is the one.

If incorrect, please someone let me know.

Best of luck.

Steve
 
hi Steve, thanks.
I re-checked my answer and realize I think I read the question wrong... Two lone pairs, meaning four all together (I was interpreting it like two, not two pairs) if that makes sense. Then I think it's XeF4.
 
Smith4046 said:
Think you are correct. The three 3p3 electrons of P should be bonded to the three Cls, each one forming single bonds. That leaves the pair of 3s2 electons unshared. Haven't even looked at the other choices, since I feel PCl3 is the one.

If incorrect, please someone let me know.

Best of luck.

Steve

The bonds are not strictly s and p bonds, but rather are spd hybridized.

PCl_{3} has only one lone pair. So, you can rule it out.

Carbon must obey the octet rule, so you can rule out iodomethane.

Try drawing Lewis structures for the other 3. One is square planar (octahedral), thanks to its two lone pairs.
 
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