Recent content by lriuui0x0
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I How to visualize 2-form or exterior product?
Let's say we have a grid of contour lines defined by df and dg, consecutive contour lines have their function values changed by one. Then does each grid cell correspond to area one?- lriuui0x0
- Post #3
- Forum: Differential Geometry
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I How to visualize 2-form or exterior product?
We can visualize 1-form by contour lines, since a 1-form / gradient sort of represents how fast the function changes. I wonder whether we can visualize 2-form df ^ dg by intersection of two sets of contour lines for f and g, or maybe something of a similar nature?- lriuui0x0
- Thread
- Product
- Replies: 5
- Forum: Differential Geometry
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I Canonical transformation vs symplectomorphism
Hmmm... I fee it's weird that the old & new coordinates are described by different charts, since they are completely not comparable that way. The transformation between the coordinates would not reflect the symplectomorphism itself, but also a random chart transition function. So is the answer...- lriuui0x0
- Post #6
- Forum: Classical Physics
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I Canonical transformation vs symplectomorphism
I'm just trying to understand in what sense symplectomorphism is canonical transformation. My understanding is the following. When you have a symplectomorphism, that's an active picture of the transformation which maps a point on the phase space to a different point. If we have a coordinate...- lriuui0x0
- Post #4
- Forum: Classical Physics
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I Canonical transformation vs symplectomorphism
I have read that canonical transformation is basically a symplectomorphism which leaves the symplectic form invariant. My understanding is that the canonical transformation is a passive picture where we keep the point on the phase space fixed and change the coordinate chart, where...- lriuui0x0
- Thread
- Canonical transformation Transformation
- Replies: 6
- Forum: Classical Physics
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I Jacobi identity of Lie algebra intuition
My intuition about the Lie algebra is that it tries to capture how infinitestimal group generators fails to commute. This means ##[a, a] = 0## makes sense naturally. However the Jacobi identity ##[a,[b,c]]+[b,[c,a]]+[c,[a,b]] = 0## makes less sense. After some search, I found this article...- lriuui0x0
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- Algebra Identity Intuition Jacobi Lie algebra
- Replies: 5
- Forum: Differential Geometry
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I Can configuration space be observer independent?
Sorry, the question may sound a bit weird. I will try to give a more detailed explanation on what structure I have in mind before rasing the question. So first, we have a 4d spacetime, there are n worldlines in the spacetime representing n particles forming a system with certain interation...- lriuui0x0
- Post #6
- Forum: Classical Physics
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I Can configuration space be observer independent?
I just don't usually see coordinate independent formulation of the configuration space.- lriuui0x0
- Post #4
- Forum: Classical Physics
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I Can configuration space be observer independent?
We can formulate the spacetime in an observer/coordinate independent way, i.e. a particle becomes a worldline in the 4d space. Then relative to each observer, the worldline can be casted to a function in R^3. However, I haven't found any reference on formulating configuration space in a...- lriuui0x0
- Thread
- Configuration Configuration space Independent Observer Space
- Replies: 5
- Forum: Classical Physics
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I Galilean transformation of non-inertial frame
I think I started to understand why it's an unnatural thing to think about Galilean transformation on non-inertial observers, because the Galilean group naturally applies to the set of all inertial observers and is in one-to-one relationship to it (not sure what's the right math word here?). I...- lriuui0x0
- Post #27
- Forum: Classical Physics
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I Galilean transformation of non-inertial frame
What I originally had in mind is below: So we have an affine spacetime ##N^4##, the associated vector space ##V^4##, with the simultaneity subspace ##V^3##. An oberserver in my mind is the combination of a smooth worldline ##\gamma: \mathbb{R} \to N^4## and a smooth orthonormal basis assignment...- lriuui0x0
- Post #24
- Forum: Classical Physics
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I Galilean transformation of non-inertial frame
Hmmmm...there must be something I understood wrongly on this (why Galilean transformation is not applicable to non-inertial frame). I will try to be a bit more explicit: Let's say the world is the 4 dimensional space with Galilean structure defined in the Arnold's. A Galilean transformation is...- lriuui0x0
- Post #15
- Forum: Classical Physics
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I Galilean transformation of non-inertial frame
Actually given the transformation is Galilean, shouldn't the ##\mathbf{a}_1## and ##\mathbf{a}_2## be the same, up to an orthogonal transformation?- lriuui0x0
- Post #7
- Forum: Classical Physics
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I Galilean transformation of non-inertial frame
If we take the definition from Arnold's The galilean group is the group of all transformations of a galilean space which preserve its structure. The elements of this group are called galilean transformations. Thus, galilean transformations are affine transformations of A^4...- lriuui0x0
- Post #5
- Forum: Classical Physics
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I Galilean transformation of non-inertial frame
It's frequently discussed Galilean transformation brings one inertial frame to another inertial frame, and such a transformation leaves Newton's second law invariant (of the same form). I wonder what happens for non-inertial frame? If we start with a non-inertial frame, and Galilean transform...- lriuui0x0
- Thread
- Frame Galilean Galilean transformation Non-inertial frame Transformation
- Replies: 35
- Forum: Classical Physics