Can configuration space be observer independent?

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We can formulate the spacetime in an observer/coordinate independent way, i.e. a particle becomes a worldline in the 4d space. Then relative to each observer, the worldline can be casted to a function in R^3. However, I haven't found any reference on formulating configuration space in a coordinate independent way. It seems that the configuration space is formed in a way with a particular observer and some particular coordinates for the state of the system. Just want to ask if there's such a concept as observer independent configuration space?
 
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Dale said:
I don’t understand. Why would configuration space be observer dependent?
I just don't usually see coordinate independent formulation of the configuration space.
 
By definition a Lagrangian system is a pair (L,M), where M is a smooth manifold called the configuration space and ##L: TM\to \mathbb{R}## is a smooth function
ok?
 
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wrobel said:
By definition a Lagrangian system is a pair (L,M), where M is a smooth manifold called the configuration space and ##L: TM\to \mathbb{R}## is a smooth function
ok?
Sorry, the question may sound a bit weird. I will try to give a more detailed explanation on what structure I have in mind before rasing the question.

So first, we have a 4d spacetime, there are n worldlines in the spacetime representing n particles forming a system with certain interation. There might be constraints at each spatial slice, such as the distance between two particles maintain the same.

These definitions are observer independent that fully describe the system, so if the configuration space is also observer independent, we should be able to derive the configuration space structure purely from the above. My question is how to craft such a definition?