Recent content by Ltpenguin

It is a Quadratic because it forms a parabola and not an exponential graph because an exponential graph would not lower at any point it would continune to go on a sharp incline. Also i still got an error when i removed x=11 / y=50 Got another calculator my seems to malfunction when doing the...

It would appear to be a quadratic but when i try to make the formula on my TI-83 it doesn't make the equation it gives and error.

Homework Statement State the mathematical relationship (Linear,Quadratic,Exponential) and determine the regression equation for this relationship. Homework Equations X| 1 | 3 | 5 | 7 | 9 | 11 | 13 | 15 | Y| 50 | 14 | 2 | 14 | 50| 50 |194|302| The Attempt at a Solution ?.? i...

First thank you all for the help :) i was wondering if a 1000w light bulb had 750w wasted energy then i would calculate the light bulb as having only 250w of useful energy so 250w over 1000w? 25 % efficiency?

Well % efficiency = 41 % yes. Although i still think since you calculate the efficiency of the hill any left over energy (400J)at the bottom of the hill is considered waste. Since you only calculate useful power output in efficiency you shouldn't use the remaining energy for your equation but...

Homework Statement A snowboarder goes down a ramp when initially at rest. The Total mechanical energy on top of the hill is 980 J and 400J at the bottom of the hill. Calculate efficiency of the ramp. Homework Equations Efficency = (Power out) over (Power in) The Attempt at a...

Homework Statement Explain the location of the poles of the electromagnet. Homework Equations RHR The Attempt at a Solution Is this correct?or are the poles opposite of what they are meant to be. I believe it is south on the left a confirmation would be great thank you :)

Alright so this is it F=mg F=5000 x 9.8m/s F=49'000 N The cable exerts 49k N force on the elevator, making the net force zero so it can move at a constant velocity.

a is the acceleration of the elevator, 2m/s

wait so it is right?

do you mean by 2m/s vs 9.8m/s2

What do you think it could be? i point in the right direction well help a ton thank you :)

I figured this out i believe: F=mg+ma F=(5000*9.8)+(5000*2) F=59'000 N i think that is correct. The Force placed by the tension cable to keep the elevator at rest is 49'000 Newtons to move the elevator at 2m/s it takes 59'000 N *updated first post check it out*

Alright so i will guess that "the force" means the force from the cable so... F=mg F=5000 x 9.8m/s F=49'000 N Is that correct? or am i missing something with the 2m/s the elevator is moving. Thanks for the help.

Homework Statement A cable lifts a 5000kg elevator at a constant velocity of 2.0m/s [up] I) Find the force acting on the elevator. II) Find displacement of the elevator in 15s. III) find the work done by the cable on the elevator over a time period of 15s. Homework Equations W=FΔd...