Calculate Efficiency of Hill for Snowboarder

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Homework Help Overview

The discussion revolves around calculating the efficiency of a ramp used by a snowboarder, with specific energy values provided for the top and bottom of the hill. The original poster presents an initial calculation based on the mechanical energy at different points and seeks clarification on the correct interpretation of efficiency.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore different interpretations of how to calculate efficiency, questioning whether to consider remaining energy as waste or useful energy. There are discussions about the correct formulation of efficiency and the implications of energy loss during the descent.

Discussion Status

The discussion is active, with participants providing differing viewpoints on the calculation of efficiency. Some participants suggest that the remaining energy should not be considered waste, while others emphasize the importance of distinguishing between useful and wasted energy. There is no explicit consensus, but various interpretations are being explored.

Contextual Notes

Participants are navigating the definitions and calculations related to efficiency, with some confusion about the correct terminology and formulation. The original poster's problem statement includes specific energy values, which are central to the discussion.

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Homework Statement



A snowboarder goes down a ramp when initially at rest. The Total mechanical energy on top of the hill is 980 J and 400J at the bottom of the hill. Calculate efficiency of the ramp.

Homework Equations



Efficency = (Power out) over (Power in)

The Attempt at a Solution


Tw7Baph.png


I believe the %59 is correct because at the bottom of the hill the snowboarder had 400 J of energy left ( waste energy) so that is not calculated in efficiency you use 980-400 = 580J is the useful energy out. is this correct?

or is it this
QfPboFE.png

Thank you for your help :)
 
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The second solution makes more sense to me. By the way, the correct form is Eff. = 41%, not %Eff. = 41 which makes no sense.
 
dauto said:
The second solution makes more sense to me. By the way, the correct form is Eff. = 41%, not %Eff. = 41 which makes no sense.

Well % efficiency = 41 % yes. Although i still think since you calculate the efficiency of the hill any left over energy (400J)at the bottom of the hill is considered waste. Since you only calculate useful power output in efficiency you shouldn't use the remaining energy for your equation but the difference i.e. 580J was used to go down the hill. Hope i am explaining it correctly.
 
To help you decide which calculation is correct...

Consider how much energy the rider would have at the bottom if the ramp was 100% efficient.
 
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Also note that 400/980 = 0.41 (considering 2 sf)
 
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Ltpenguin said:
Well % efficiency = 41 % yes. Although i still think since you calculate the efficiency of the hill any left over energy (400J)at the bottom of the hill is considered waste. Since you only calculate useful power output in efficiency you shouldn't use the remaining energy for your equation but the difference i.e. 580J was used to go down the hill. Hope i am explaining it correctly.

No, not % efficiency = 41 %. As I said that is not correct. The correct way is efficiency = 41%. Keep in mind that % is just a shorthand for (1/100). Than if efficiency = 0.41 we have

Efficiency = 0.41 = 41/100 = 41*(1/100) = 41%.

There is no % sign before the word efficiency. That's just wrong.

Also, the Mechanical energy at the bottom of the hill is the reason snowboarders like going down a hill. It makes no sense to call it waste since that energy was the motivation to go uphill to begin with. that 41% is the useful energy. The waste is the 59% that was lost along the way down the hill.
 
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First thank you all for the help :) i was wondering if a 1000w light bulb had 750w wasted energy then i would calculate the light bulb as having only 250w of useful energy so 250w over 1000w? 25 % efficiency?
 
Ltpenguin said:
First thank you all for the help :) i was wondering if a 1000w light bulb had 750w wasted energy then i would calculate the light bulb as having only 250w of useful energy so 250w over 1000w? 25 % efficiency?

Yes indeed
 
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