Calculate Efficiency of Hill for Snowboarder

  • Thread starter Thread starter Ltpenguin
  • Start date Start date
  • Tags Tags
    Efficiency Hill
AI Thread Summary
The discussion focuses on calculating the efficiency of a ramp for a snowboarder, with total mechanical energy of 980 J at the top and 400 J at the bottom. The correct efficiency is determined to be 41%, calculated by considering the useful energy output of 580 J (980 J - 400 J) against the total input energy. Participants clarify that the remaining energy at the bottom is not waste but part of the energy used for motion, emphasizing that the lost energy accounts for the inefficiency. The conversation also touches on the proper notation for expressing efficiency, highlighting the distinction between efficiency and percentage efficiency. Overall, the key takeaway is that the ramp's efficiency is 41%, with 59% of energy considered wasted.
Ltpenguin
Messages
15
Reaction score
0

Homework Statement



A snowboarder goes down a ramp when initially at rest. The Total mechanical energy on top of the hill is 980 J and 400J at the bottom of the hill. Calculate efficiency of the ramp.

Homework Equations



Efficency = (Power out) over (Power in)

The Attempt at a Solution


Tw7Baph.png


I believe the %59 is correct because at the bottom of the hill the snowboarder had 400 J of energy left ( waste energy) so that is not calculated in efficiency you use 980-400 = 580J is the useful energy out. is this correct?

or is it this
QfPboFE.png

Thank you for your help :)
 
Physics news on Phys.org
The second solution makes more sense to me. By the way, the correct form is Eff. = 41%, not %Eff. = 41 which makes no sense.
 
dauto said:
The second solution makes more sense to me. By the way, the correct form is Eff. = 41%, not %Eff. = 41 which makes no sense.

Well % efficiency = 41 % yes. Although i still think since you calculate the efficiency of the hill any left over energy (400J)at the bottom of the hill is considered waste. Since you only calculate useful power output in efficiency you shouldn't use the remaining energy for your equation but the difference i.e. 580J was used to go down the hill. Hope i am explaining it correctly.
 
To help you decide which calculation is correct...

Consider how much energy the rider would have at the bottom if the ramp was 100% efficient.
 
  • Like
Likes 1 person
Also note that 400/980 = 0.41 (considering 2 sf)
 
  • Like
Likes 1 person
Ltpenguin said:
Well % efficiency = 41 % yes. Although i still think since you calculate the efficiency of the hill any left over energy (400J)at the bottom of the hill is considered waste. Since you only calculate useful power output in efficiency you shouldn't use the remaining energy for your equation but the difference i.e. 580J was used to go down the hill. Hope i am explaining it correctly.

No, not % efficiency = 41 %. As I said that is not correct. The correct way is efficiency = 41%. Keep in mind that % is just a shorthand for (1/100). Than if efficiency = 0.41 we have

Efficiency = 0.41 = 41/100 = 41*(1/100) = 41%.

There is no % sign before the word efficiency. That's just wrong.

Also, the Mechanical energy at the bottom of the hill is the reason snowboarders like going down a hill. It makes no sense to call it waste since that energy was the motivation to go uphill to begin with. that 41% is the useful energy. The waste is the 59% that was lost along the way down the hill.
 
  • Like
Likes 1 person
First thank you all for the help :) i was wondering if a 1000w light bulb had 750w wasted energy then i would calculate the light bulb as having only 250w of useful energy so 250w over 1000w? 25 % efficiency?
 
Ltpenguin said:
First thank you all for the help :) i was wondering if a 1000w light bulb had 750w wasted energy then i would calculate the light bulb as having only 250w of useful energy so 250w over 1000w? 25 % efficiency?

Yes indeed
 
  • Like
Likes 1 person
Back
Top