Recent content by lucifer_x

ohhh ok that makes sense thank you for making it more clear so the almost final will look like this 43=A(15625)+B(625)+C(25)+D then you divide them ??

ya that's what it is, there are 4 points on the curve so like (x_1,y_1)=(25,43) is what i was thinking but that's only one point

so how would i put the points of A into y(x)=Ax^3+Bx^2+Cx+D cause there are 2 points and only 1 A

the curve points are: a) (25, 43) b) (28, 46) c) (32, 47) d) (35, 45) would i use y=mx+b i think that's a straight line

i don't know what half of 2/3 is or 4/3 because if i know that then i can square them and that's it i calculated : (x² - 2/3x + 1/9) + (y² + 4/3 + 2/3) = 22/9 is this it

ok let me try, thanks then its all fractions: x² - 2/3x + y² + 4/3 = 22/9

Homework Statement 9x² + 9y² - 6x + 12y - 22 = 0 Homework Equations The Attempt at a Solution i got this far but can't finish i don't know what to do: 3(3x² - 2x + 1) + 3(3y² + 4y + 4) = 40

i need to write the general form of a conic setion with foci @ ( -2, -1 ) and ( 6 , -1 ) and a y-int of 1.75 what would b the first step

so would the answer be y = - 2/3 sin ( 2Θ + π ) and y = 2/3 sin ( 2Θ + π ) ??

Homework Statement If tan^-1 (3/5) = Θ , what is csc^-1 (cotanΘ) i don't get the question

Homework Statement Write an equation of a sine function with a amp=(2/3) , Period = 4╥ and a phase shift of ╥/2. in radians Homework Equations The Attempt at a Solution i got y = 2/3 cos (2...

if csc theta= x-6 x-2 and ctn theta= x+5 x-2 find theta

how would i write the depressed polynomial for the obvious root of f(x) = x5 - .5x4 - 5.5x3 - 3.5x2 - 6.5x - 3

thanks a bunch, after i knew that i was set A= 4 B= -7

decomposed into TWO "simpler" fractions how would this be decomposed into TWO "simpler" fractions, thanks f(x) = -10x - 7 2x2- 17x +21