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the curve points are:
a) (25, 43)
b) (28, 46)
c) (32, 47)
d) (35, 45)
would i use y=mx+b i think thats a straight line
a) (25, 43)
b) (28, 46)
c) (32, 47)
d) (35, 45)
would i use y=mx+b i think thats a straight line
Unfortunately the points don't all lie on the same quadratic, so a cubic is necessary.my guess is that you only need [tex]y(x) = Ax^2 + Bx + C[/tex].
I thought a), b) c) and d) were each points on the curve in the form [itex](x_1,y_1)=(25,43)[/itex] etc.....is this assumption incorrect?so how would i put the points of A into
[tex]y(x)=Ax^3+Bx^2+Cx+D[/tex]
cause there are 2 points and only 1 A